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Question

Solve the following. 

Subtract $\frac{9}{2} + \frac{x}{2} + \frac{3}{5}x^2 + \frac{7}{4}x^3$ from $\frac{7}{2} - \frac{x}{3} - \frac{1}{5}x^2$.

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper PDF (31-Jan-2021) (Shift 1)
The correct answer is
$-1 - \frac{5}{6}x - \frac{4}{5}x^2 - \frac{7}{4}x^3$

Polynomial Subtraction Steps

To solve the problem, we need to subtract the first expression from the second expression. This means we set up the subtraction as:

$ \left( \frac{7}{2} - \frac{x}{3} - \frac{1}{5}x^2 \right) - \left( \frac{9}{2} + \frac{x}{2} + \frac{3}{5}x^2 + \frac{7}{4}x^3 \right) $

Simplify the Expression

Distribute the negative sign to each term in the second expression:

$ \frac{7}{2} - \frac{x}{3} - \frac{1}{5}x^2 - \frac{9}{2} - \frac{x}{2} - \frac{3}{5}x^2 - \frac{7}{4}x^3 $

Combine Like Terms

Group and combine terms with the same power of $x$:

  • Constant terms: $ \frac{7}{2} - \frac{9}{2} = \frac{7 - 9}{2} = \frac{-2}{2} = -1 $
  • Terms with $x$: $ -\frac{x}{3} - \frac{x}{2} = x \left( -\frac{1}{3} - \frac{1}{2} \right) = x \left( \frac{-2 - 3}{6} \right) = -\frac{5}{6}x $
  • Terms with $x^2$: $ -\frac{1}{5}x^2 - \frac{3}{5}x^2 = x^2 \left( -\frac{1}{5} - \frac{3}{5} \right) = x^2 \left( \frac{-1 - 3}{5} \right) = -\frac{4}{5}x^2 $
  • Terms with $x^3$: $ -\frac{7}{4}x^3 $

Final Result

Combine the simplified terms to get the final expression:

$ -1 - \frac{5}{6}x - \frac{4}{5}x^2 - \frac{7}{4}x^3 $

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Important Questions from Polynomials

  1. Identify the correct statement with respect to the polynomial (S+1) (S+2) (S+3) (S+4)
  2. Two circles have radius in the ratio \(4 : 3\), write a polynomial to express the combined total surface area of the two circles.
  3. If $x=2$ is one of the zeros of the polynomial $x^3 - 6x^2 + 11x - 6$, which are the other two zeros?
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