The question asks for the total volume of a cuboid formed by combining six identical cubes, each with a side length of 4 cm. These cubes are placed adjacent to each other.
The most straightforward method to find the volume of the resulting cuboid is to sum the volumes of the individual cubes. This approach is independent of how the cubes are arranged.
The formula for the volume of a cube is $V_{\text{cube}} = s^3$, where $s$ represents the side length.
Given the side length $s = 4$ cm, the volume of one cube is calculated as:
$ V_{\text{cube}} = (4 \text{ cm})^3 $ $ V_{\text{cube}} = 4 \times 4 \times 4 \text{ cm}^3 $ $ V_{\text{cuboid}} = 64 \text{ cm}^3 $
Since there are 6 identical cubes, the total volume ($V_{\text{total}}$) of the cuboid formed is 6 times the volume of a single cube.
$ V_{\text{total}} = \text{Number of cubes} \times V_{\text{cube}} $ $ V_{\text{total}} = 6 \times 64 \text{ cm}^3 $ $ V_{\text{total}} = 384 \text{ cm}^3 $
The volume of the cuboid formed by placing six adjacent cubes, each with a side length of 4 cm, is 384 cm$^3$.
There is a wooden block in the form of a cube whose each side is 8 meters long.
The maximum possible number of cylinders with a diameter of 1 meter and a height of 4 meters were cut from this block. The cylinders are to be painted at the rate of ₹14 per square meter.
What is the total amount (in ₹) needed to paint all the cylinders if we paint the entire surface of each cylinder? (Take $\pi = \frac{22}{7}$)