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Question

Simplify : (√6 – 2√3)2

The correct answer is

18 – 12√2

This is a common type of problem involving squaring a binomial that contains square roots. In this case, the constant terms (6 and 12) were combined, while the term with the square root (12\sqrt{2}) remained separate because it is not a like term. Therefore, the correct answer is 18 – 12√2.

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Important Questions from Identities

  1. If \(2x + { {1} \over 3x}= 5, x ≠ 0\) , then what is the value of  \(27x^3+{{1} \over 8x^3}\) ?

  2. If x 2 + 4y 2 = 40, xy = 6 and x > 2y then the value of x - 2y is:

  3. \(\dfrac{(0.73)^3+(0.31)^3}{(0.73)^2-0.73\times0.31+(0.31)^2}\)
  4. \(\dfrac{(5.17-2.19)^2-(5.17+2.19)^2}{11.3223}\)
  5. If a(a + b + c) 2= 1792; b(a + b + c) 2= 1536; c(a + b + c) 2= 768 then what will be the value of a?

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