Simplify : (√6 – 2√3)2
18 – 12√2
This is a common type of problem involving squaring a binomial that contains square roots. In this case, the constant terms (6 and 12) were combined, while the term with the square root (12\sqrt{2}) remained separate because it is not a like term. Therefore, the correct answer is 18 – 12√2.
If \(2x + { {1} \over 3x}= 5, x ≠ 0\) , then what is the value of \(27x^3+{{1} \over 8x^3}\) ?
If x 2 + 4y 2 = 40, xy = 6 and x > 2y then the value of x - 2y is:
If a(a + b + c) 2= 1792; b(a + b + c) 2= 1536; c(a + b + c) 2= 768 then what will be the value of a?