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Simplify: \(\left(1+\frac{q^2-p^2-r^2}{2pr}\right)\times\left(\frac{1}{q+p-r}+\frac{1}{r+q-p}\right)\)

This question was previously asked in
RRB Technician 2026 Grade 3 Question Paper (7-Oct-2026) (Shift 3)
The correct answer is

\(\frac{q}{pr}\)

First bracket: \(1+\frac{q^2-p^2-r^2}{2pr} = \frac{q^2-(p^2-2pr+r^2)}{2pr} = \frac{q^2-(p-r)^2}{2pr}\).

Using \(a^2-b^2=(a-b)(a+b)\): \(\frac{(q-p+r)(q+p-r)}{2pr}\).

Second bracket: \(\frac{1}{q+p-r}+\frac{1}{r+q-p} = \frac{(r+q-p)+(q+p-r)}{(q+p-r)(r+q-p)} = \frac{2q}{(q+p-r)(r+q-p)}\).

Product: \(\frac{(q-p+r)(q+p-r)}{2pr}\times\frac{2q}{(q+p-r)(q-p+r)} = \frac{q}{pr}\).

Hence, the expression simplifies to \(\frac{q}{pr}\).

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