If a square has a side of (11x – 9) cm, then the area of the square (in cm2) is:
121x2 – 198x + 81
The area of a square of side a is \(a^2\), and \((a - b)^2 = a^2 - 2ab + b^2\).
Area = \((11x - 9)^2 = (11x)^2 - 2(11x)(9) + 9^2\).
So the area = \(121x^2 - 198x + 81\) cm2.
Check: put x = 1; the side is 11 – 9 = 2 cm and the area is 4 cm2, while 121 – 198 + 81 = 4, which agrees.
Hence, 121x2 – 198x + 81.
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