The problem requires us to find the initial amount deposited for Mandar so that both grandsons receive equal amounts at age 23, given a total deposit and an annual compound interest rate.
Let \(P_R\) be the principal amount deposited for Rupesh and \(P_M\) be the principal amount deposited for Mandar. The total deposit is ₹23400.
So, \(P_R + P_M = 23400\).
The interest rate is 8% per annum, compounded annually. \(r = 0.08\).
Rupesh is 14 years old and will receive the money at 23. The time period for Rupesh's investment is \(t_R = 23 - 14 = 9\) years.
Mandar is 15 years old and will receive the money at 23. The time period for Mandar's investment is \(t_M = 23 - 15 = 8\) years.
The future value (Amount, \(A\)) is calculated using the formula \(A = P(1 + r)^t\). Both grandsons should receive the same amount when they turn 23.
Amount for Rupesh: \(A_R = P_R(1 + 0.08)^9 = P_R(1.08)^9\).
Amount for Mandar: \(A_M = P_M(1 + 0.08)^8 = P_M(1.08)^8\).
Since \(A_R = A_M\), we have:
\(P_R(1.08)^9 = P_M(1.08)^8\)We can simplify the equation to find the relationship between \(P_R\) and \(P_M\):
\(P_R = P_M \frac{(1.08)^8}{(1.08)^9}\) \(P_R = P_M \frac{1}{1.08}\)Now substitute the expression for \(P_R\) into the total deposit equation (\(P_R + P_M = 23400\)):
\(P_M \left(\frac{1}{1.08}\right) + P_M = 23400\)Factor out \(P_M\):
\(P_M \left(\frac{1}{1.08} + 1\right) = 23400\) \(P_M \left(\frac{1 + 1.08}{1.08}\right) = 23400\) \(P_M \left(\frac{2.08}{1.08}\right) = 23400\)Solve for \(P_M\):
\(P_M = 23400 \times \frac{1.08}{2.08}\) \(P_M = 23400 \times \frac{108}{208}\)Simplify the fraction \(\frac{108}{208} = \frac{27}{52}\).
\(P_M = 23400 \times \frac{27}{52}\)Perform the calculation:
\(P_M = \frac{23400}{52} \times 27\) \(P_M = 450 \times 27\) \(P_M = 12150\)Therefore, Shivam deposited ₹12150 in the name of Mandar.
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