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Question

Saturated steam at 100°C is condensing on shell side of a shell and tube heat exchanger. The cooling water enters the tube at 30°C and leaves at 70°C. Calculate arithmetic mean temperature difference in counter flow arrangement.

The correct answer is

50°C

Condensing steam remains at 100°C. The two end temperature differences are 100−30=70°C and 100−70=30°C. Their arithmetic mean is (70+30)/2=50°C.

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Important Questions from Heat Exchanger Analysis

  1. The logarithmic mean temperature difference for parallel flow heat exchangers is

  2. The fin effectiveness can be enhanced by selecting _____ value of heat transfer co-efficient.

  3. A cold liquid enters a counter flow heat exchanger at 15 deg at a rate of 8 kg/s. A hot stream of the same liquid enters the heat exchanger at 75 deg at 2 kg/s. Assuming the specific heat of the fluid as 4 kJ/kg.°C, determine the maximum heat transfer rate.

  4. For the same inlet and exit temperatures of the hot and cold fluids, the Log mean temperature difference (LMTD) is

  5. In a heat exchanger, the hot liquid enters with a temperature of 180°C and leaves at 160°C. The cooling fluid enters at 30°C and leaves at 110°C. The capacity ratio of the heat exchanger is

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