The problem states that the variable S varies directly as the expression (R + 7). This means there's a constant relationship between S and (R + 7). We can write this relationship using a mathematical equation.
Direct variation can be expressed as:
$S \propto (R + 7)$
To turn this proportionality into an equation, we introduce a constant of variation, usually denoted by k:
$S = k(R + 7)$
We are given an initial condition: S = 42 when R = 17. We can use these values to find the value of the constant k.
Substitute the given values into the equation:
$42 = k(17 + 7)$
First, simplify the term in the parentheses:
$42 = k(24)$
Now, solve for k by dividing both sides by 24:
$k = \frac{42}{24}$
Simplify the fraction. Both 42 and 24 are divisible by 6:
$k = \frac{42 \div 6}{24 \div 6} = \frac{7}{4}$
So, the constant of variation is $k = \frac{7}{4}$.
Now we need to find the value of S when R = 29. We use the same equation $S = k(R + 7)$, but this time with the newly found value of k and the new value of R.
Substitute $k = \frac{7}{4}$ and $R = 29$ into the equation:
$S = \frac{7}{4}(29 + 7)$
First, calculate the sum inside the parentheses:
$S = \frac{7}{4}(36)$
Now, perform the multiplication. We can divide 36 by 4 first:
$S = 7 \times \frac{36}{4}$
$S = 7 \times 9$
Finally, calculate the result:
$S = 63$
Therefore, when R = 29, the value of S is 63.
Meena sells 70 red marbles and 105 blue marbles in boxes without mixing such that each box has x number of marbles. What is the value of x?
If 3A = 4B = 5C, then A : B : C is equal to:
Divide Rs. 156 in the ratio 1 : 2 : 4 : 5. The rupees in the respective ratios are given by:
A. 13, 26, 53 & 64
B. 13, 26, 51 & 66
C. 13, 26, 52 & 65
D. 13, 25, 53 & 65The ratio of the third proportion of 5 and 12 with the fourth proportion of 5, 8 and 9 is:
Mrs. Deepa Devi saves 30% of her salary. If she receives Rs. 42,000 per month as her salary, what is her monthly expenditure?