A simply supported beam has a span of 6 m with an overhang of 4 m. A uniformly distributed load (UDL) of 6 kN/m acts over the overhang length of 4 m. What is the reaction at the nearest support?
32 kN
To find the reaction at the nearest support of a simply supported beam with an overhang, follow these steps:
Given:
Steps to solve:
The total load \(W_{\text{total}}\) acting on the overhang is given by:\)
The equivalent point load acts at the midpoint of the overhang, which is \(2\, \text{m}\) from the end of the overhang.
Let the reaction at the nearest support be \(R_A\). Taking moments about point A (the nearest support):
\(R_A \times 0 = W_{\text{total}} \times ( \text{L} + ( L_{\text{overhang}}/2 ) )\),
\(R_A \times 0 = 24 \times (6 + 2)\)
\(R_A = \frac{24 \times 8}{6} = 32 \, \text{kN}\)
Therefore, the reaction at the nearest support (point A) is \(32 \, \text{kN}\).
Conclusion:
The correct answer is 32 kN.
Hence, the reaction at the nearest support is 32 kN.
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