Rama and Hari can together finish a piece of work in 15 day. Rama works twice as fast as Hari, then Hari alone can finish work in :
45 days
This problem involves understanding the concept of work rate and how it relates to the time taken to complete a task. When people work together, their work rates add up.
Work rate is the amount of work done per unit of time. If someone completes a task in \(D\) days, their work rate is \( \frac{1}{D} \) of the work per day.
Let's denote the time taken by Hari alone to finish the work as \(H\) days.
Hari's work rate per day will be \( \frac{1}{H} \).
The problem states that Rama works twice as fast as Hari. This means Rama's work rate is double Hari's work rate.
Rama's work rate per day is \( 2 \times \frac{1}{H} = \frac{2}{H} \).
When Rama and Hari work together, their individual work rates add up to form their combined work rate.
Combined work rate = Hari's work rate + Rama's work rate
Combined work rate \( = \frac{1}{H} + \frac{2}{H} = \frac{1+2}{H} = \frac{3}{H} \).
This means they complete \( \frac{3}{H} \) of the work per day when working together.
We know that Rama and Hari together finish the work in 15 days. The relationship between work rate and time is:
\( \text{Work Rate} \times \text{Time} = \text{Total Work} \)
Since they complete the entire work, the total work is considered as 1 unit.
\( \left(\text{Combined work rate}\right) \times \left(\text{Time taken together}\right) = 1 \)
\( \left(\frac{3}{H}\right) \times 15 = 1 \)
Now, we can solve the equation for \(H\):
\( \frac{3 \times 15}{H} = 1 \)
\( \frac{45}{H} = 1 \)
To find \(H\), we can cross-multiply:
\( 45 = H \times 1 \)
\( H = 45 \)
So, Hari alone can finish the work in 45 days.
Therefore, Hari alone can finish the work in 45 days.
| Person/Group | Work Rate (per day) | Time Taken Alone (days) |
|---|---|---|
| Hari | \( \frac{1}{H} \) | \( H \) (which we found to be 45) |
| Rama | \( \frac{2}{H} \) | \( \frac{H}{2} \) (since rate is double, time is half, i.e., \( \frac{45}{2} = 22.5 \)) |
| Rama and Hari Together | \( \frac{3}{H} \) | 15 (Given) |
| Concept | Explanation | Formula/Relationship |
|---|---|---|
| Work Rate | The amount of work done per unit of time. | If time is \(T\), Work Rate \( = \frac{1}{T} \) (assuming total work is 1 unit). |
| Time Taken | The duration required to complete a certain amount of work. | Time \( = \frac{\text{Total Work}}{\text{Work Rate}} \). |
| Combined Work Rate | The sum of individual work rates when multiple people work together. | Rate\(_{A+B}\) = Rate\(_{A}\) + Rate\(_{B}\). |
| Total Work | Often considered as 1 unit when comparing different rates and times. | Total Work \( = \) Work Rate \( \times \) Time. |
Work rate problems often involve scenarios where individuals or machines work at different speeds to complete a task. Key to solving these problems is converting the time taken into a rate of work (amount of work per unit time).
In this specific Rama and Hari problem, using the efficiency relationship (Rama is twice as fast as Hari) directly allowed us to define their rates relative to each other and then use the combined time to find the unknown time for Hari.
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