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Question

Raju obtained 75 and 85 marks in mathematics and physics, respectively. Find the marks he must get in chemistry to have an average of 80 marks in all the three subjects.

The correct answer is
80

To find the marks Raju must get in chemistry to have an average of 80 marks across mathematics, physics, and chemistry, we can use the formula for calculating the average. The average of three subjects is given by:

\text{Average} = \frac{\text{Sum of scores in all subjects}}{\text{Number of subjects}}

We know:

  • Marks in Mathematics = 75
  • Marks in Physics = 85
  • Required average = 80

Let the marks Raju needs in chemistry be x. Therefore, the equation for the average becomes:

\frac{75 + 85 + x}{3} = 80

Solving this equation:

75 + 85 + x = 80 \times 3

160 + x = 240

x = 240 - 160

x = 80

Therefore, Raju must score 80 in chemistry to have an average of 80 marks in all three subjects.

This matches the given correct answer, so option B, 80, is correct.

To ensure clarity:

  • x = 80 ensures the sum of marks = 75 + 85 + 80 = 240, and dividing by 3 gives the average as 80.
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Important Questions from Average (Notes)

  1. The average age of a group of boys and girls is 18 years. If the average age of boys is 20 years and that of girls is 15 years, then what is the percentage of boys in the group?
  2. The average of 13 numbers is 8. If each number is multiplied by 7, then what will the new average be:
  3. There are 78 members in group A, 22 members in group B and 34 members in group C. All the members of these groups went to a restaurant. The average amounts spent on each member of groups A, B and C are ₹136, ₹383 and ₹457, respectively. The overall average amount (in ₹) spent per member is:
  4. If the average of p numbers is $q^2$ and that of q numbers is $p^2$, then the average of (p + q) numbers is :
  5. The average of 101 consecutive odd numbers is 303. Find the largest number.
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