All Exams Test series for 1 year @ ₹349 only
Question

Pipe A can fill a tank in 6 hours. Pipe B can empty it in 15 hours. If both the pipes are opened together, then the tank will be filled in how many hours?

This question was previously asked in
RRB ALP 2018 CBT 2 Fitter Question Paper (21-Jan-2019) (Shift 3)
The correct answer is

10

Understanding the Tank Filling and Emptying Problem

This question involves two pipes, one filling a tank and the other emptying it. To solve this, we need to understand the rate at which each pipe works individually and then calculate their combined effect when working together.

Calculating Individual Pipe Rates

  • Pipe A is a filling pipe. It fills the tank in 6 hours. This means in 1 hour, Pipe A fills \(\frac{1}{6}\) of the tank. The filling rate of Pipe A is \(\frac{1}{6}\) tank per hour.
  • Pipe B is an emptying pipe. It empties the tank in 15 hours. This means in 1 hour, Pipe B empties \(\frac{1}{15}\) of the tank. The emptying rate of Pipe B is \(\frac{1}{15}\) tank per hour. Note that emptying is the opposite of filling, so its contribution is negative in the combined calculation.

Finding the Combined Rate of Filling

When both pipes are opened together, their rates combine. Since Pipe A is filling and Pipe B is emptying, the net rate at which the tank is being filled is the difference between the filling rate and the emptying rate.

Combined rate = (Rate of Pipe A) - (Rate of Pipe B)

Combined rate = \(\frac{1}{6} - \frac{1}{15}\) tank per hour.

Calculating the Combined Rate

To subtract these fractions, we need a common denominator. The least common multiple (LCM) of 6 and 15 is 30.

  • Convert \(\frac{1}{6}\) to a fraction with denominator 30: \(\frac{1}{6} \times \frac{5}{5} = \frac{5}{30}\)
  • Convert \(\frac{1}{15}\) to a fraction with denominator 30: \(\frac{1}{15} \times \frac{2}{2} = \frac{2}{30}\)

Now, subtract the fractions:

Combined rate = \(\frac{5}{30} - \frac{2}{30} = \frac{5 - 2}{30} = \frac{3}{30}\)

Simplify the combined rate:

Combined rate = \(\frac{3}{30} = \frac{1}{10}\) tank per hour.

This means that when both pipes are open, \(\frac{1}{10}\) of the tank is filled every hour.

Determining the Time to Fill the Tank

If \(\frac{1}{10}\) of the tank is filled in 1 hour, then the total time taken to fill the entire tank (which is 1 whole tank) is the reciprocal of the combined rate.

Time taken = \(\frac{1}{\text{Combined rate}}\)

Time taken = \(\frac{1}{\frac{1}{10}}\) hours

Time taken = \(1 \times \frac{10}{1}\) hours

Time taken = 10 hours.

Therefore, if both pipes are opened together, the tank will be filled in 10 hours.

Revision Table: Key Concepts

Concept Description Formula
Individual Rate (Filling) Fraction of work done by a filling pipe in one unit of time (e.g., 1 hour). \(\frac{1}{\text{Time taken to fill}}\)
Individual Rate (Emptying) Fraction of work done by an emptying pipe in one unit of time. Treated as negative work. \(\frac{-1}{\text{Time taken to empty}}\)
Combined Rate The net fraction of work done by all pipes together in one unit of time. Sum of individual rates. Sum of individual rates (filling rates are positive, emptying rates are negative)
Time Taken (Combined) The total time required to complete the work (fill the tank) at the combined rate. \(\frac{1}{\text{Combined rate}}\) (if combined rate is positive, meaning filling is faster than emptying)

Additional Information on Tank Filling Problems

Problems involving pipes and tanks are often solved using the concept of 'work rate'. Here's a bit more detail:

  • Work Rate: If a job (like filling a tank) can be completed in 'T' units of time, the rate of work is \(1/T\) of the job per unit of time.
  • Multiple Workers (Pipes): When multiple pipes work together, their individual work rates are added to find the combined work rate.
  • Filling vs. Emptying: Filling pipes contribute positively to the work (filling the tank), while emptying pipes contribute negatively (emptying the tank). So, when both types are involved, you subtract the emptying rate from the filling rate.
  • Total Work: The total work is typically considered as '1 unit' (representing the full tank).
  • Time = Total Work / Combined Rate: This fundamental relationship is used to find the time taken when the combined rate is known.

It's important to ensure the combined rate is positive for the tank to actually fill up. If the combined rate were negative (meaning the emptying rate is higher than the filling rate), the tank would be emptied, not filled, and the question might ask for the time taken to empty a full tank instead.

Was this answer helpful?

Similar Questions

  1. Two pipes A and B can fill an empty cistern in 32 and 48 hours, respectively. Pipe C can drain the entire cistern in 64 hours when no other pipe is in operation. Initially, when the cistern was empty Pipe A and Pipe C were turned on. After a few hours, Pipe A was turned off and Pipe B was turned on instantly. In all it took 112 hours to fill the cistern. For how many hours was Pipe B turned on?

  2. Pipes A, B and C are attached to an empty cistern. While the first two can fill the cistern in 4 and 10 hours, respectively, the third can drain the cistern, when filled, in 6 hours. If all the three pipes are opened simultaneously when the cistern is three-fifth full, how many hours will be needed to fill the cistern?

  3. One pipe can fill an empty cistern in 4 hours while another can drain the cistern when full in 10 hours. Both the pipes were turned on when the cistern was half-empty. How long will it take the cistern to be full?

  4. A pipe, working at full speed, can fill an empty cistern in 1 hour. However, during the first hour it worked at one-twelfth of its capacity, during the second hour at one-ninth of its capacity, during the third hour at one-sixth of its usual capacity, during the fourth hour at one- fourth of its usual capacity and during the fifth hour it was only one-third as efficient as it was supposed to be. A second pipe also displayed similar performance, but if it worked at full speed would have filled the empty cistern in 2 hours. Together with a drain pipe that drained water out of the tank at a constant rate, the empty cistern could be filled in 5 hours, all the three pipes working concurrently. How many hours will it take the drain pipe to empty the filled cistern if no other pipe was functioning during the time?

  5. One of the two inlet pipes works twice as efficiently as the other. The two, working alongside a drain pipe that can empty a cistern all by itself in 8 hours, can fill the empty cistern in 8 hours. How many hours will the less efficient inlet pipe take to fill the empty cistern by itself?

  6. Two pipes, when working one at a time can fill a cistern in 2 hours and 3 hours, respectively while a third pipe can drain the cistern empty in 6 hours. All the three pipes were opened together when the cistern was 1/6 full. How long will it take for the cistern to be completely full?

  7. A tanker can fill a cistern in 12 hours. After half the cistern is filled, 2 more similar tankers are opened. What is the time taken to fill the remaining half of the tank?

  8. P, Q and R are channels which discharge solutions A, B, C respectively in a tank. When the tank is empty and all the three channels are opened what is the proportion of the solution C in the tank after 3 minutes, if the channels P, Q and R can fill the tank from empty to full in 30 minutes and 20 minutes and 10 minutes respectively when they are opened one at a time.

  9. A sump is filled by three tankers with uniform flow. The first two tankers operating simultaneously fill the sump in the same time during which the sump is filled by the third tanker alone. The second tanker fills the sump 5 hours faster than the first tanker and 4 hours slower than the third tanker. The time required by the first tanker is:

  10. Two pipes fill a tank when working individually in 25 and 40 hours, respectively while a third pipe can drain the filled tank in 16 hours. If all the three pipes are turned on at the same time when the tank is empty, how long will it take to fill the tank completely?

Important Questions from Pipe and Cistern

  1. Two pipes A and B can independently fill a tank completely in 20 and 30 minutes respectively. If both the pipes are opened simultaneously, how much time will they take to fill the tank completely?

  2. The compound interest on Rs. 64,000 for 3 years, compounded annually at 7.5% p.a. is

  3. A water tank can be emptied in 40 minutes by a pipe of d 'diameter, so how long will it take for a 2d diameter pipe to be emptied?

  4. A pipe can fill a tank in 4 hours, while a leak which is at one-fourth of the height of the tank from bottom can empty upto that part in 2 hours. If both are operated simultaneously and initially the tank is full, then when it will be one-fourth full?

  5. Two pipes X and Y can fill an empty tank in 16 hours and 20 hours respectively. Pipe Z alone can empty the completely filled tank in 25 hours. Firstly both pipes X and Y are opened and after 6 hours pipe Z is also opened. What will be the total time (in hours) taken to completely fill the tank?

Need Expert Advice?
Upcoming Exams
RRB Technician
October 06, 2026
RRB JE
October 27, 2026
RRB ALP
November 03, 2026
Test Series
RRB ALP img
Railways
RRB ALP 2026 Mock Test series
1035 Tests 1 Tests Free
1082 Attempts
4.3(238)
English, Hindi

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App