One year ago the ratio of the ages of two sister was 2 : 3. The sum of their present ages is 12. What are their ages now?
5, 7
This problem asks us to find the present ages of two sisters given information about the ratio of their ages one year ago and the sum of their present ages.
We are provided with two key pieces of information:
Our goal is to determine the present age of each sister.
Let's denote the present age of the first sister as $A$ and the present age of the second sister as $B$.
From the given information, we can form two equations:
Now we have a system of two linear equations with two variables:
$$A + B = 12$$ $$3A - 3 = 2B - 2$$We can use the substitution method to solve this system.
From Equation 1, we can express $B$ in terms of $A$:
$$B = 12 - A$$Substitute this expression for $B$ into Equation 2:
$$3A - 3 = 2(12 - A) - 2$$ $$3A - 3 = 24 - 2A - 2$$ $$3A - 3 = 22 - 2A$$Now, rearrange the equation to bring all terms with $A$ to one side and constants to the other side:
$$3A + 2A = 22 + 3$$ $$5A = 25$$Divide by 5 to find the value of $A$:
$$A = \frac{25}{5}$$ $$A = 5$$So, the present age of the first sister is 5 years.
Now, substitute the value of $A$ back into Equation 1 ($B = 12 - A$) to find the value of $B$:
$$B = 12 - 5$$ $$B = 7$$So, the present age of the second sister is 7 years.
Let's check if these ages satisfy the original conditions:
Since both conditions are satisfied, our calculated ages are correct.
The calculated present ages are 5 and 7. Let's compare this with the provided options:
Our result (5, 7) matches Option 1.
The present ages of the two sisters are 5 years and 7 years.
| Concept | Description | How it applies here |
| Present Age | Age of a person currently. | Represented by variables $A$ and $B$. |
| Age in the Past/Future | Age $x$ years ago is Present Age $- x$. Age $y$ years in the future is Present Age $+ y$. |
Age one year ago is Present Age $- 1$. Used $(A-1)$ and $(B-1)$. |
| Ratio | Comparison of two quantities by division. | Used the ratio $\frac{A-1}{B-1} = \frac{2}{3}$. |
| Sum | The result of adding numbers. | Used the sum $A+B=12$. |
| System of Equations | A set of two or more equations solved together. | We had two equations ($A+B=12$ and $3(A-1)=2(B-1)$) to solve for $A$ and $B$. |
| Substitution Method | Solving a system of equations by expressing one variable from one equation and substituting it into the other equation. | Used to solve for $A$ and $B$. |
Age problems are common in mathematics and often appear in competitive exams. Here are some strategies to tackle them:
Practicing different types of age problems will help you become more comfortable with setting up and solving the equations.
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