Understanding the Meeting Schedule Puzzle

This problem involves determining the specific day each of the 7 people (A, B, C, D, E, F, and G) attends a meeting. We are given a set of clues and need to deduce the complete schedule. The key information is that the week starts on Monday, and we need to find out when person E attends their meeting.

The days of the week, starting from Monday, can be numbered as follows:

• Monday: Day 1
• Tuesday: Day 2
• Wednesday: Day 3
• Thursday: Day 4
• Friday: Day 5
• Saturday: Day 6
• Sunday: Day 7

We will use these clues to build the schedule step by step.

Step-by-Step Deduction of the Schedule

1. Initial Placement of B: The first clue states that B attends a meeting on Thursday. Thursday is Day 4.
   • Schedule: _, _, _, B, _, _, _
2. Positioning G relative to B: We know that only one person attends the meeting between B and G. This gives us two possibilities for G's position:
   • Possibility 1: G attends on Day 2 (Monday), with the person on Day 3 between G and B. Schedule: _, G, _, B, _, _, _
   • Possibility 2: G attends on Day 6 (Saturday), with the person on Day 5 between B and G. Schedule: _, _, _, B, _, G, _
3. Positioning A relative to G: The clue states that A attends the meeting immediately after G.
   • Applying this to Possibility 1 (G on Day 2): A must be on Day 3. Schedule: _, G, A, B, _, _, _
   • Applying this to Possibility 2 (G on Day 6): A must be on Day 7 (Sunday). Schedule: _, _, _, B, _, G, A
4. Relating A's and C's positions: The clue is: The number of people who attend a meeting before A is the same as the number of people who attend the meeting after C. Mathematically, $\text{Count}(\text{Days before A}) = \text{Count}(\text{Days after C})$.
   • In Possibility 1 (A on Day 3): There are 2 people before A (G and the person on Day 2). So, there must be 2 people after C. If C is on Day 5, then the people on Day 6 and Day 7 are after C. This fits. The schedule becomes: _, G, A, B, C, _, _ (Remaining days: 1, 6, 7 for D, E, F).
   • In Possibility 2 (A on Day 7): There are 6 people before A (Days 1 through 6). So, there must be 6 people after C. This implies C must be on Day 1 (Monday). The schedule becomes: C, _, _, B, _, G, A (Remaining days: 2, 3, 5 for D, E, F).
5. Positioning D relative to C: We are told that only one person attends a meeting between C and D.
   • Checking Possibility 1 (C on Day 5): With C on Day 5, D must be on Day 7 to have one person (on Day 6) between them. Schedule: _, G, A, B, C, _, D. The remaining days are 1 and 6 for persons E and F.
   • Checking Possibility 2 (C on Day 1): With C on Day 1, D must be on Day 3 to have one person (on Day 2) between them. Schedule: C, _, D, B, _, G, A. The remaining days are 2 and 5 for persons E and F.
6. Positioning F relative to D: The clue is F attends the meeting after D.
   • Revisiting Possibility 1 (D on Day 7): If D is on Day 7, F cannot attend *after* D, as there are no more days. Therefore, Possibility 1 is incorrect.
   • Revisiting Possibility 2 (D on Day 3): The available days for the remaining people (E, F) are Day 2 and Day 5. Since F must attend after D (Day 3), F must be scheduled on Day 5. Schedule: C, _, D, B, F, G, A.
7. Final Placement of E: With Possibility 2 being the only valid one, the schedule is C, _, D, B, F, G, A. The remaining person is E, and the only remaining day is Day 2 (Tuesday).
   • Final Schedule: C, E, D, B, F, G, A

Final Meeting Schedule

Based on the deductions, the complete meeting schedule is:

Determining E's Meeting Day

Looking at the finalized schedule, we can clearly see the day assigned to each person. Person E is scheduled to attend the meeting on Tuesday.