Neha starts from Point A and drives 11 km towards the east. She then takes a right turn, drives 8 km, turns right and drives 14 km. She then takes a right turn and drives 12 km. She takes a final right turn, drives 3 km and stops at Point P. How far (shortest distance) and towards which direction should she drive in order to reach Point A again? (All turns are 90-degree turns only unless specified.)
4 km to the south
Place A at the origin \((0, 0)\) with east as \(+x\) and north as \(+y\).
Drive 11 km east: reach \((11, 0)\).
Right turn now faces south; drive 8 km: reach \((11, -8)\).
Right turn now faces west; drive 14 km: reach \((11 - 14, -8) = (-3, -8)\).
Right turn now faces north; drive 12 km: reach \((-3, -8 + 12) = (-3, 4)\).
Right turn now faces east; drive 3 km: reach \((-3 + 3, 4) = (0, 4)\), which is Point P.
P is at \((0, 4)\) and A is at \((0, 0)\); they share the same \(x\), so P is 4 km due north of A.
Therefore Neha must drive 4 km to the south to reach Point A again.
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