Meeta travels 4 km towards north and then travels 5 km eastward. She then travels 10 km rightwards, and then 3 km to the left and finally 5 km northwards. How far is she approximately from his original destination and in what direction?
8 km towards south east
Let's track Meeta's movement step-by-step to find her final position relative to her starting point. We can imagine the starting point as the origin (0,0) on a coordinate system, where North is the positive y-axis, South is the negative y-axis, East is the positive x-axis, and West is the negative x-axis.
Her final position is at coordinates (8, -1). The starting point was (0,0).
The displacement from the origin (0,0) to the final position (8, -1) can be found using the distance formula, which is based on the Pythagorean theorem. The horizontal displacement is 8 units (East) and the vertical displacement is -1 unit (South).
Distance = $\sqrt{(\text{Change in x})^2 + (\text{Change in y})^2}$
Distance = $\sqrt{(8 - 0)^2 + (-1 - 0)^2}$
Distance = $\sqrt{8^2 + (-1)^2}$
Distance = $\sqrt{64 + 1}$
Distance = $\sqrt{65}$ km
The value of $\sqrt{65}$ is approximately 8.06 km.
The question asks for the approximate distance.
The final position is at (8, -1). This means the final position is 8 units in the positive x-direction (East) and 1 unit in the negative y-direction (South) from the starting point (0,0).
A position that is East and South of the origin is in the South-East direction.
Meeta is approximately 8.06 km away from her original destination. The direction from the original destination to her final position is South-East.
Comparing this result with the given options:
The approximate distance is 8 km and the direction is towards south-east.
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