What will come in place of 'X', and \(X > 0\), in the equation \(\dfrac{X}{125} = \dfrac{5}{X}\)
25
Cross-multiply the equation \(\dfrac{X}{125} = \dfrac{5}{X}\) to get \(X \times X = 5 \times 125\).
So \(X^{2} = 625\).
Taking the positive square root (since \(X > 0\)): \(X = \sqrt{625} = 25\).
Hence, the value of X is 25.
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