Let's analyze the question to determine who got the highest marks among Brijesh, Paresh, Ramesh, Naresh, and Suresh.
- It's given that all five students have distinct marks.
- The marks of Brijesh are the average of all the students' marks. This implies: \(B = \frac{P + R + N + S + B}{5}\) Simplifying this gives: \(5B = P + R + N + S + B\) \(4B = P + R + N + S\)
- The marks of Naresh are the average of the marks of Paresh and Ramesh: \(N = \frac{P + R}{2}\) Hence, \(2N = P + R\)
- Paresh has the least marks, so \(P\) is the smallest.
- It's stated that Naresh has more marks than Suresh: \(N > S\).
- By substituting some assumptions and conditions, we will aim to find who has the highest marks. Given that \(P\) is the smallest and \(N > S\), it leaves Brijesh and Ramesh as potential candidates for the highest marks.
- However, since Brijesh's marks are the average of all, his marks are dependent on others and hence unlikely to be highest given distinct values.
- Ramesh appears not to have any conditions directly linking his marks to others, giving potential for his marks to be high. Since Naresh's marks are the average of Paresh and Ramesh, Ramesh's marks have to be higher than Naresh to satisfy other conditions (like distinct marks).
Thus, from logical deduction based on given conditions, Ramesh has the highest marks.