We are given a set of \(2 \times 2\) matrices \( \text{A} = \begin{bmatrix} a & b \\ c & d \end{bmatrix} \) with elements \( a, b, c, d \in \{0, 1, 2, 3, 4\} \), satisfying the equation:
\(A^2 - 4A + 3I = 0\)
We need to find the number of matrices in this set for which the sum of the diagonal elements (\(a + d\)) is equal to 4.
Hence, the number of matrices in the set \(S\) for which the sum of the diagonal elements is 4 is 19.
Let S be the set of the first 11 natural numbers. Then the number of elements in $A = \{B \subseteq S : n(B) \geq 2$ and the product of all elements of B is even is ________.
If $ \left(\frac{1}{^{15}C_0} + \frac{1}{^{15}C_1}\right)$ $\left(\frac{1}{^{15}C_1} + \frac{1}{^{15}C_2}\right)$ $\dots$ $ \left(\frac{1}{^{15}C_{12}} + \frac{1}{^{15}C_{13}}\right)$ = $\frac{\alpha^{13}}{^{14}C_0 ^{14}C_1 \dots ^{14}C_{12}} $, then $30\alpha$ is equal to __________.
Let S be the set of the first 11 natural numbers. Then the number of elements in $A = \{B \subseteq S : n(B) \geq 2$ and the product of all elements of B is even is ________.