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Question

Let p(z) = z3 + (1 + j) z2 + (2 + j) z + 3, where z is a complex number.

Which one of the following is true?  

The correct answer is

All the roots cannot be real

By Viète’s formula the sum of the three roots is −(1 + j), which is nonreal. Thus they cannot all be real. Also a monic polynomial whose full root multiset consists of real roots and conjugate pairs has real coefficients, unlike this polynomial. Conjugation symmetry fails, for example at z = 1: p(1) = 7 + 2j.

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Important Questions from Complex Variables

  1. Let $z = x + iy$ be a complex variable and $\bar{z}$ be its complex conjugate. The equation$z^2 + \bar{z}^2 = 2$ represents a
  2. Consider the complex function $f(z) = \cos z + e^{z^2}$. The coefficient of $z^5$ in the Taylor series expansion of $f(z)$ about the origin is ________ (rounded off to 1 decimal place).
  3. Let $f(z) = j \frac{1-z}{1+z}$, where z denotes a complex number and j denotes $\sqrt{-1}$. The inverse function $f^{-1}(z)$ maps the real axis to the ______.
  4. The contour integral $$\oint_C e^{1/z} dz$$ with C as the counter-clockwise unit circle in the z-plane is equal to

  5. Let $$ I = \int_0^1 \frac{1}{1+t} dt + \frac{\pi i}{2} \int_0^1 \frac{1}{1+e^2} dt - i \int_0^1 \frac{1}{1+it} dt, $$ where $ t $ is a real variable and $ i = \sqrt{-1} $. The value of $ I $ is ______________

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