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Question

Given \(f(z)=\frac{1}{z+1}-\frac{2}{z+3}\). If C is a counterclockwise path in the z-plane such that |z + 1| = 1, the value of \(\frac{1}{2\pi i}\int_c f(z)dz\) is

The correct answer is

1

The circle is centred at−1 with radius1. It encloses the pole at−1, residue1, and excludes−3. Dividing the counterclockwise contour integral by2πi therefore gives 1.

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Important Questions from Complex Variables

  1. Let $z = x + iy$ be a complex variable and $\bar{z}$ be its complex conjugate. The equation$z^2 + \bar{z}^2 = 2$ represents a
  2. Consider the complex function $f(z) = \cos z + e^{z^2}$. The coefficient of $z^5$ in the Taylor series expansion of $f(z)$ about the origin is ________ (rounded off to 1 decimal place).
  3. Let $f(z) = j \frac{1-z}{1+z}$, where z denotes a complex number and j denotes $\sqrt{-1}$. The inverse function $f^{-1}(z)$ maps the real axis to the ______.
  4. The contour integral $$\oint_C e^{1/z} dz$$ with C as the counter-clockwise unit circle in the z-plane is equal to

  5. Let $$ I = \int_0^1 \frac{1}{1+t} dt + \frac{\pi i}{2} \int_0^1 \frac{1}{1+e^2} dt - i \int_0^1 \frac{1}{1+it} dt, $$ where $ t $ is a real variable and $ i = \sqrt{-1} $. The value of $ I $ is ______________

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