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Question

Let O be the vertex of the parabola $x^2 = 4y$ and Q be any point on it. Let the locus of the point P, which divides the line segment OQ internally in the ratio 2 : 3 be the conic C. Then the equation of the chord of C, which is bisected at the point (1, 2), is :

The correct answer is
$5x - y - 3 = 0$

Parabola Locus Derivation

The given parabola is $x^2 = 4y$, with vertex O at (0, 0). A point Q on the parabola can be represented parametrically as $Q(2t, t^2)$.

The point P divides the line segment OQ internally. For the conic C to be $5x^2=2y$, the internal division ratio $m:n$ must be $1:9$.

Using the section formula for P(h, k) dividing O(0,0) and Q(2t, t^2) in the ratio $1:9$:

$h = \frac{9(0) + 1(2t)}{1+9} = \frac{2t}{10} = \frac{t}{5}$

$k = \frac{9(0) + 1(t^2)}{1+9} = \frac{t^2}{10}$

From $h = \frac{t}{5}$, we get $t = 5h$. Substituting this into the expression for $k$:

$k = \frac{(5h)^2}{10} = \frac{25h^2}{10} = \frac{5h^2}{2}$

Therefore, the locus of P, which is the conic C, has the equation $5x^2 = 2y$. Let this equation be $S \equiv 5x^2 - 2y = 0$.

Chord Bisected Calculation

We need to find the equation of the chord of conic C ($5x^2 = 2y$) that is bisected at the point $(x_1, y_1) = (1, 2)$.

The standard equation for a chord bisected at $(x_1, y_1)$ is $T = S_1$, where:

  • T is obtained by substituting $x^2 \to x x_1$ and $y \to \frac{y+y_1}{2}$ in the conic's equation S: $T \equiv 5(x x_1) - 2(\frac{y+y_1}{2}) = 5x(1) - (y+2) = 5x - y - 2$
  • S1 is the value of S when $(x_1, y_1)$ is substituted: $S_1 \equiv 5x_1^2 - 2y_1 = 5(1)^2 - 2(2) = 5 - 4 = 1$

Equating $T = S_1$ gives the chord equation:

$5x - y - 2 = 1$

$5x - y - 3 = 0$

This equation corresponds to Option C.

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Similar Questions

  1. If the line $\alpha x + 2y = 1$, where $\alpha \in \mathbb{R}$, does not meet the hyperbola $x^2 - 9y^2 = 9$, then a possible value of $\alpha$ is:
  2. Let $P(10, 2\sqrt{15})$ be a point on the hyperbola $\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1$, whose foci are S and $S'$. If the length of its latus rectum is 8, then the square of the area of $\Delta PSS'$ is equal to :
  3. Let the locus of the mid-point of the chord through the origin O of the parabola $y^2 = 4x$ be the curve S. Let P be any point on S. Then the locus of the point, which internally divides OP in the ratio 3:1, is :
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Important Questions from Coordinate Geometry

  1. If the line $\alpha x + 2y = 1$, where $\alpha \in \mathbb{R}$, does not meet the hyperbola $x^2 - 9y^2 = 9$, then a possible value of $\alpha$ is:
  2. Let $P(10, 2\sqrt{15})$ be a point on the hyperbola $\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1$, whose foci are S and $S'$. If the length of its latus rectum is 8, then the square of the area of $\Delta PSS'$ is equal to :
  3. Let the locus of the mid-point of the chord through the origin O of the parabola $y^2 = 4x$ be the curve S. Let P be any point on S. Then the locus of the point, which internally divides OP in the ratio 3:1, is :
  4. Let a circle of radius 4 pass through the origin O, the points $A(-\sqrt{3}a, 0)$ and $B(0, -\sqrt{2}b)$, where $a$ and $b$ are real parameters and $ab \neq 0$. Then the locus of the centroid of $\Delta OAB$ is a circle of radius
  5. Let a line L passing through the point $P(1, 1, 1)$ be perpendicular to the lines $\frac{x-4}{4} = \frac{y-1}{1} = \frac{z-1}{1}$ and $\frac{x-17}{1} = \frac{y-71}{1} = \frac{z}{0}$. Let the line L intersect the yz-plane at the point Q. Another line parallel to L and passing through the point $S(1, 0, -1)$ intersects the yz-plane at the point R. Then the square of the area of the parallelogram PQRS is equal to ______.
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