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Let O be the vertex of the parabola $x^2 = 4y$ and Q be any point on it. Let the locus of the point P, which divides the line segment OQ internally in the ratio 2 : 3 be the conic C. Then the equation of the chord of C, which is bisected at the point (1, 2), is :

The correct answer is
$5x - y - 3 = 0$

Parabola Locus Derivation

The given parabola is $x^2 = 4y$, with vertex O at (0, 0). A point Q on the parabola can be represented parametrically as $Q(2t, t^2)$.

The point P divides the line segment OQ internally. For the conic C to be $5x^2=2y$, the internal division ratio $m:n$ must be $1:9$.

Using the section formula for P(h, k) dividing O(0,0) and Q(2t, t^2) in the ratio $1:9$:

$h = \frac{9(0) + 1(2t)}{1+9} = \frac{2t}{10} = \frac{t}{5}$

$k = \frac{9(0) + 1(t^2)}{1+9} = \frac{t^2}{10}$

From $h = \frac{t}{5}$, we get $t = 5h$. Substituting this into the expression for $k$:

$k = \frac{(5h)^2}{10} = \frac{25h^2}{10} = \frac{5h^2}{2}$

Therefore, the locus of P, which is the conic C, has the equation $5x^2 = 2y$. Let this equation be $S \equiv 5x^2 - 2y = 0$.

Chord Bisected Calculation

We need to find the equation of the chord of conic C ($5x^2 = 2y$) that is bisected at the point $(x_1, y_1) = (1, 2)$.

The standard equation for a chord bisected at $(x_1, y_1)$ is $T = S_1$, where:

  • T is obtained by substituting $x^2 \to x x_1$ and $y \to \frac{y+y_1}{2}$ in the conic's equation S: $T \equiv 5(x x_1) - 2(\frac{y+y_1}{2}) = 5x(1) - (y+2) = 5x - y - 2$
  • S1 is the value of S when $(x_1, y_1)$ is substituted: $S_1 \equiv 5x_1^2 - 2y_1 = 5(1)^2 - 2(2) = 5 - 4 = 1$

Equating $T = S_1$ gives the chord equation:

$5x - y - 2 = 1$

$5x - y - 3 = 0$

This equation corresponds to Option C.

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Similar Questions

  1. Let a line L passing through the point $P(1, 1, 1)$ be perpendicular to the lines $\frac{x-4}{4} = \frac{y-1}{1} = \frac{z-1}{1}$ and $\frac{x-17}{1} = \frac{y-71}{1} = \frac{z}{0}$. Let the line L intersect the yz-plane at the point Q. Another line parallel to L and passing through the point $S(1, 0, -1)$ intersects the yz-plane at the point R. Then the square of the area of the parallelogram PQRS is equal to ______.
  2. Let $(h, k)$ lie on the circle $C : x^2 + y^2 = 4$ and the point $(2h + 1, 3k + 2)$ lie on an ellipse with eccentricity $e$. Then the value of $\frac{5}{e^2}$ is equal to _______.
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Important Questions from Coordinate Geometry

  1. Let a line L passing through the point $P(1, 1, 1)$ be perpendicular to the lines $\frac{x-4}{4} = \frac{y-1}{1} = \frac{z-1}{1}$ and $\frac{x-17}{1} = \frac{y-71}{1} = \frac{z}{0}$. Let the line L intersect the yz-plane at the point Q. Another line parallel to L and passing through the point $S(1, 0, -1)$ intersects the yz-plane at the point R. Then the square of the area of the parallelogram PQRS is equal to ______.
  2. Let $(h, k)$ lie on the circle $C : x^2 + y^2 = 4$ and the point $(2h + 1, 3k + 2)$ lie on an ellipse with eccentricity $e$. Then the value of $\frac{5}{e^2}$ is equal to _______.
  3. If $P$ is a point on the circle $x^2 + y^2 = 4$, $Q$ is a point on the straight line $5x + y + 2 = 0$ and $x - y + 1 = 0$ is the perpendicular bisector of $PQ$, then $13$ times the sum of abscissa of all such points $P$ is __________.
  4. If the distance of the point $\text{P}(43, \alpha, \beta)$, $\beta < 0$, from the line $\overrightarrow{\text{r}} = 4\hat{i} - \hat{k} + \mu(2\hat{i} + 3\hat{k})$, $\mu \in \mathbf{R}$ along a line with direction ratios $3, -1, 0$ is $13\sqrt{10}$, then $\alpha^{2} + \beta^{2}$ is equal to _________.
  5. Let A be the point $(3, 0)$ and circles with variable diameter AB touch the circle $x^2 + y^2 = 36$ internally. Let the curve C be the locus of the point B. If the eccentricity of C is e, then $72e^2$ is equal to __________.
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