The function given is \( f(x) = x - [x] \), where \( x \ge 0 \). The term \( [x] \) denotes the greatest integer function, which returns the largest integer less than or equal to \( x \). The function \( f(x) \) specifically calculates the fractional part of \( x \).
Consider the function's behavior over an interval between two consecutive integers, say \( [n, n+1) \), where \( n \) is any non-negative integer.
Because \( f(x) = x - n \) has a positive slope (\( 1 \)) within the interval \( [n, n+1) \), the function increases linearly as \( x \) increases in this range.
While the function drops to 0 at every integer value of \( x \) (since \( f(n+1) = (n+1) - [n+1] = (n+1) - (n+1) = 0 \)), its behavior *between* any two consecutive integers is consistently linear and increasing.
Therefore, the function \( f(x) = x - [x] \) is a linearly increasing function between two integers.
Consider the hyperbolic functions in Group – 1 and their definitions in Group - 2.
| Group - 1 | Group - 2 | ||
| P | $\tanh x$ | I | $\frac{e^x + e^{-x}}{e^x - e^{-x}}$ |
| Q | $\coth x$ | II | $\frac{2}{e^x + e^{-x}}$ |
| R | $\text{sech } x$ | III | $\frac{2}{e^x - e^{-x}}$ |
| S | $\text{cosech } x$ | IV | $\frac{e^x - e^{-x}}{e^x + e^{-x}}$ |
The correct combination is