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Question

Let $f$ be a function such that $f (x)+3f (\frac{24}{x}) = 4x, x \neq 0$. Then $f (3) + f (8)$ is equal to

The correct answer is
11

Solving the Functional Equation

We are given the functional equation: $f (x)+3f (\frac{24}{x}) = 4x$, where $x \neq 0$. We need to find the value of $f (3) + f (8)$.

Evaluating the Function at Specific Points

Substitute $x = 3$ into the equation:

$f (3)+3f (\frac{24}{3}) = 4(3)$

$f (3)+3f (8) = 12 \quad \cdots (1)$

Substitute $x = 8$ into the equation:

$f (8)+3f (\frac{24}{8}) = 4(8)$

$f (8)+3f (3) = 32 \quad \cdots (2)$

Solving the System of Equations

We now have a system of two linear equations with two variables, $f(3)$ and $f(8)$:

  1. $f(3) + 3f(8) = 12$
  2. $3f(3) + f(8) = 32$

Multiply Equation (1) by 3:

$3(f(3) + 3f(8)) = 3(12)$

$3f(3) + 9f(8) = 36 \quad \cdots (3)$

Subtract Equation (2) from Equation (3):

$(3f(3) + 9f(8)) - (3f(3) + f(8)) = 36 - 32$

$8f(8) = 4

$f(8) = \frac{4}{8} = \frac{1}{2}

Substitute the value of $f(8)$ back into Equation (1):

$f(3) + 3(\frac{1}{2}) = 12$

$f(3) + \frac{3}{2} = 12$

$f(3) = 12 - \frac{3}{2} = \frac{24}{2} - \frac{3}{2} = \frac{21}{2}

Calculating the Final Value

We need to find $f(3) + f(8)$.

$f(3) + f(8) = \frac{21}{2} + \frac{1}{2} = \frac{22}{2} = 11

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Important Questions from Algebra

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