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Let \(A = \{-3,-2,-1, 0, 1, 2, 3\}\) and \(B = \{0, 1, 4, 9\}\). How many elements does the subset of \(A \times B\) corresponding to the relation \(R = \{(x, y): |x| < y\}\) have, where \(x \in A\) and \(y \in B\)?

This question was previously asked in
NDA 2 2025 GAT Question Paper (14-Sep-2025)
The correct answer is

15

To solve the problem, we need to determine the number of elements in the subset of \(A \times B\) that satisfy the relation \(R = \{(x, y): |x| < y\}\) where \(x \in A\) and \(y \in B\).

First, let's break down the problem:

  • \(A = \{-3, -2, -1, 0, 1, 2, 3\}\)
  • \(B = \{0, 1, 4, 9\}\)

The condition \(R = \{(x, y): |x| < y\}\) means that for every pair \((x, y)\), the absolute value of \(x\) must be less than \(y\).

Let's check each \(y\) in set \(B\) and find suitable \(x\) that satisfy the relation:

  1. For \(y = 0\)
    • No values of \(x\) satisfy \(|x| < 0\). Hence, no suitable pairs.
  2. For \(y = 1\)
    • Satisfies for \(x = 0\). (1 pair: (0, 1))
  3. For \(y = 4\)
    • Satisfies for \(x = -3, -2, -1, 0, 1, 2, 3\). (7 pairs: (-3, 4), (-2, 4), (-1, 4), (0, 4), (1, 4), (2, 4), (3, 4))
  4. For \(y = 9\)
    • Satisfies for all \(x = -3, -2, -1, 0, 1, 2, 3\). (7 pairs: (-3, 9), (-2, 9), (-1, 9), (0, 9), (1, 9), (2, 9), (3, 9))

To find the total number of elements in the relation \(R\), we sum up the pairs found:

  • Pairs with \(y = 0\): 0
  • Pairs with \(y = 1\): 1
  • Pairs with \(y = 4\): 7
  • Pairs with \(y = 9\): 7

Total number of pairs: \(0 + 1 + 7 + 7 = 15\).

Thus, the correct number of elements in the subset is 15.

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