This problem requires calculating the time for a raft to drift downstream using given steamboat travel times.
Let:
The steamboat travels downstream (A to B) and upstream (B to A).
Using the relationship $Distance = Speed × Time$:
Rearranging the equations:
To find the current speed ($S_c$), subtract the second rearranged equation from the first:
$(D/5) - (D/7) = (S_s + S_c) - (S_s - S_c)$
$D * (1/5 - 1/7) = 2 * S_c$
Combine the fractions:
$D * ((7 - 5) / 35) = 2 * S_c$
$D * (2 / 35) = 2 * S_c$
Solve for $S_c$:
$S_c = D / 35$
A raft drifts only with the river current, so its speed is equal to $S_c$.
The time taken for the raft to travel distance $D$ is calculated as:
$Time_raft = Distance / Speed_raft$
$Time_raft = D / S_c$
Substitute the value of $S_c$ derived earlier:
$Time_raft = D / (D / 35)$
Simplify the expression:
$Time_raft = 35$
Thus, the raft will take 35 days to drift from A to B.
A and B have to travel from place P to place Q following the same route in their respective cars. A drives at $60$ kmph while B drives at $80$ kmph. Find the time taken by B to reach place Q if A takes $12$ hrs.
On a straight road, a bus is $60$ km ahead of a car running in the same direction. After $3$ hours, the car is $90$ km ahead of the bus. If the speed of the bus is $45$ km/h, then what is the speed of the car (in km/h)?
A train running at the speed of $90$ kmph crosses a $250$ m long platform in $26$ seconds. What is the length of the train (in m)?
A car covers 4 successive stretches of 3 km each at speed of 10 kmph, 20 kmph, 30 kmph and 60 kmph respectively. The average speed of the car for the entire journey is: