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Question

In this question, three statements are given, followed by two conclusions numbered I and II. Assuming the statements to be true, even if they seem to be at variance with commonly known facts, decide which of the conclusions logically follows/follow from the statements. 

Statements: 

I. Some bamboos are sticks. 

II. All canes are sticks. 

III. All canes are twigs. 

Conclusions: 

I. Some bamboos are twigs. 

II. Some twigs are sticks.

This question was previously asked in
SSC Selection Post 2024 Question Paper (26-Jun-2024) (Shift-4)
The correct answer is
Only conclusion II follows

Logical Analysis of Statements and Conclusions

This question requires us to evaluate logical conclusions based on a set of given statements. We need to determine if the conclusions necessarily follow from the statements, assuming the statements are true.

Analyzing the Statements

Let's break down each statement and understand the relationship between the categories mentioned:

  • Statement I: Some bamboos are sticks. This means there is at least one bamboo that is also a stick. In set notation, if B represents the set of bamboos and S represents the set of sticks, then the intersection is not empty: $B \cap S \neq \emptyset$.
  • Statement II: All canes are sticks. This means the entire set of canes is included within the set of sticks. If C represents the set of canes, then $C \subset S$.
  • Statement III: All canes are twigs. This means the entire set of canes is also included within the set of twigs. If T represents the set of twigs, then $C \subset T$.

Evaluating the Conclusions

Now, let's examine each conclusion based on the information from the statements:

  • Conclusion I: Some bamboos are twigs.

    Statement I tells us about the relationship between bamboos and sticks ($B \cap S \neq \emptyset$). Statements II and III link canes to sticks and twigs ($C \subset S$ and $C \subset T$). However, there's no information connecting bamboos directly or indirectly to twigs. It's possible that the bamboos which are sticks are not twigs, and the twigs (which include canes) are separate from these specific bamboos. Therefore, this conclusion does not necessarily follow from the given statements.

  • Conclusion II: Some twigs are sticks.

    From Statement II, we know that all canes are sticks ($C \subset S$). From Statement III, we know that all canes are twigs ($C \subset T$). Since the set of canes (C) is a subset of both the set of sticks (S) and the set of twigs (T), it means that any member of the set C is both a stick and a twig. Assuming there exists at least one cane (the sets are not empty), then there must be entities that are both twigs and sticks. Therefore, the statement "Some twigs are sticks" logically follows. In set notation, since $C \subset S$ and $C \subset T$, their intersection $S \cap T$ contains C, meaning $S \cap T \neq \emptyset$.

Logical Deduction Summary

We established the following relationships:

  • Bamboos and Sticks have some overlap.
  • Canes are entirely within Sticks.
  • Canes are entirely within Twigs.

From these, we can see that the category 'Canes' serves as a link. Since all canes are twigs and all canes are sticks, the category 'Twigs' must contain entities (namely, canes) that are also 'Sticks'. This validates Conclusion II.

However, the overlap between 'Bamboos' and 'Sticks' doesn't guarantee any overlap with 'Twigs'. The 'bamboos' that are 'sticks' could exist in a part of the 'sticks' category that does not overlap with the 'twigs' category (which contains 'canes').

Final Determination

Based on the logical analysis, only Conclusion II necessarily follows from the given statements.

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