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Question

In the reactions

(i) nH2O + Cl– → [Cl(H2O)n]–

(ii) 6H2O + Mg2+ → [Mg(H2O)6]2+

water acts as :

This question was previously asked in
MH SET 2020 Paper 2 Philosophy Question Paper (27-Dec-2020)
The correct answer is

an acid in (i) and base in (ii)

In the Lewis picture an acid is an electron-pair acceptor and a base is an electron-pair donor. Solvation of ions by water can therefore involve water in either role, depending on which end of the water molecule faces the ion.

In reaction (i) the anion Cl– is hydrated. Its lone pairs are donated towards the slightly positive hydrogen atoms of water, forming O–H···Cl– hydrogen bonds. Water accepts electron density through its O–H σ* orbital, so it behaves as an acid (a hydrogen-bond donor, or Lewis acid) towards chloride.

In reaction (ii) the small, highly charged cation Mg2+ has vacant orbitals. Each of six water molecules donates an oxygen lone pair to the metal to give the aqua complex [Mg(H2O)6]2+, so water behaves as a Lewis base (a ligand).

Thus water is an acid in the chloride hydration and a base in the magnesium hydration. Calling it an acid in both, a base in both, or a base towards chloride and an acid towards Mg2+ reverses at least one of these electron-pair directions.

an acid in (i) and base in (ii) option is correct.

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