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Question

The carbonyl stretching frequency (νCO) for the complexes (i) [Co(CO)4]- (ii) [Ni(CO)4] and (iii) [Fe(CO)4]2- will follow the trend :

This question was previously asked in
MH SET 2019 Paper 2 Sociology Question Paper (23-Jun-2019)
The correct answer is

(ii) > (i) > (iii)

All three are isoelectronic d10 tetrahedral carbonyls

More negative charge on the metal = more M→CO π back-donation into CO π* = weaker C-O bond = lower νCO

Charge: [Ni(CO)4] = 0, [Co(CO)4]- = -1, [Fe(CO)4]2- = -2

νCO ≈ 2060 cm-1 (Ni) > 1890 cm-1 (Co) > 1790 cm-1 (Fe)

Hence, (ii) > (i) > (iii).

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