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Question

In stepwise polymerization, the addition of a small amount of catalyst results into :

The correct answer is

Reduction in time required for reaching high degree of polymerization

In step-growth (stepwise) polymerization the degree of polymerization is set by the extent of reaction p through the Carothers equation \(\bar{X}_{n} = \frac{1}{1-p}\); high polymer is obtained only at p very close to 1.

For an externally catalysed polyesterification the kinetics are second order and \(\frac{1}{1-p} = 1 + k'[M]_{0}t\), so \(\bar{X}_{n}\) grows linearly with time with slope \(k'[M]_{0}\).

Adding a catalyst increases the rate constant \(k'\), so a given extent of reaction, and therefore a high degree of polymerization, is reached in a shorter time.

A catalyst speeds up the esterification rather than lowering it, and it does not lengthen the reaction time. The molecular weight distribution at a given conversion is governed by p alone, so the distinctive effect of the catalyst is kinetic: it shortens the time needed.

Therefore the catalyst reduces the time required for reaching a high degree of polymerization.

Hence, Reduction in time required for reaching high degree of polymerization.

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