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Question

In cyclophosphazenes, $(NPX_2)_3$ (X = F, Cl, Br and Me), the strength of P-N $\pi$-bond varies with X in the order

The correct answer is
$F > Cl > Br > Me$

Cyclophosphazene P-N $\pi$-Bond Strength Variation

The P-N bond in cyclophosphazenes, represented by the general formula $(NPX_2)_3$, exhibits partial double bond character due to $\pi$-electron delocalization. This delocalization involves the phosphorus d-orbitals and nitrogen p-orbitals.

Substituent (X) Influence on $\pi$-Bond Strength

The strength of this P-N $\pi$-bond is significantly influenced by the nature of the substituent 'X' attached to the phosphorus atoms. Generally, more electronegative substituents enhance the $\pi$-character of the P-N bond, leading to increased bond strength.

Electronegativity and Bond Strength Correlation

The electronegativity of the substituents follows the order: $F > Cl > Br$. The methyl group (Me) is considered electropositive relative to the halogens.

  • Fluorine (F): Being the most electronegative, it strongly withdraws electron density, enhancing the P-N $\pi$-bond character and strength.
  • Chlorine (Cl) and Bromine (Br): These are less electronegative than Fluorine. While they contribute to $\pi$-bond character, the effect decreases down the group (Cl > Br).
  • Methyl (Me): This group is electron-donating, which reduces the $\pi$-bond character and consequently weakens the P-N bond compared to halogen substituents.

Observed P-N $\pi$-Bond Strength Order

Considering the electronegativity effects and orbital interactions, the strength of the P-N $\pi$-bond in $(NPX_2)_3$ varies with the substituent X in the following order:

$F > Cl > Br > Me$

This order corresponds to Option A.

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Important Questions from p Block Elements

  1. Borax on treatment with NaOH and $H_2O_2$ forms X. The compound X on reaction with PhCN at $60$ °C in methanol-water mixture gives Y as the major product. 
    X and Y, respectively, are

  2. The reaction of $P_2O_5$ with $HNO_3$ and $HClO_4$, respectively, gives
  3. The ease of formation of the adduct, $NH_3 \cdot BX_3$ (where, $X = F, Cl, Br$) follows the order
  4. Ammonolysis of $S_2Cl_2$ in an inert solvent gives
  5. Among the following, the group of molecules that undergoes rapid hydrolysis is
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