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Question

Ammonolysis of $S_2Cl_2$ in an inert solvent gives

The correct answer is
$S_4N_4$

Ammonolysis Product of $S_2Cl_2$ Identified

Ammonolysis involves reacting a substance with ammonia ($NH_3$). This reaction breaks and reforms chemical bonds using ammonia.

Reaction: $S_2Cl_2$ with Ammonia

The reaction of disulfur dichloride ($S_2Cl_2$) with ammonia ($NH_3$) occurs in an inert solvent. This process typically leads to the formation of sulfur-nitrogen compounds.

Key Product: $S_4N_4$

  • The primary inorganic product resulting from the ammonolysis of $S_2Cl_2$ is tetrasulfur tetranitride ($S_4N_4$).
  • Ammonium chloride ($NH_4Cl$) is also usually formed as a byproduct.

Reaction Overview

While the specific reaction pathway and stoichiometry can be complex depending on conditions, the main sulfur-containing product is $S_4N_4$. A simplified representation highlights this transformation: $ S_2Cl_2 + NH_3 \rightarrow S_4N_4 + NH_4Cl $ (Note: This equation needs balancing for accurate representation.)

Therefore, the ammonolysis of $S_2Cl_2$ in an inert solvent yields $S_4N_4$.

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Important Questions from p Block Elements

  1. The phosphazene compound that acts as a superbase is
  2. In cyclophosphazenes, $(NPX_2)_3$ (X = F, Cl, Br and Me), the strength of P-N $\pi$-bond varies with X in the order
  3. The ease of formation of the adduct, $NH_3 \cdot BX_3$ (where, $X = F, Cl, Br$) follows the order
  4. The reaction of $P_2O_5$ with $HNO_3$ and $HClO_4$, respectively, gives
  5. Among the following, the group of molecules that undergoes rapid hydrolysis is
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