Ammonolysis Product of $S_2Cl_2$ Identified
Ammonolysis involves reacting a substance with ammonia ($NH_3$). This reaction breaks and reforms chemical bonds using ammonia.
Reaction: $S_2Cl_2$ with Ammonia
The reaction of disulfur dichloride ($S_2Cl_2$) with ammonia ($NH_3$) occurs in an inert solvent. This process typically leads to the formation of sulfur-nitrogen compounds.
Key Product: $S_4N_4$
- The primary inorganic product resulting from the ammonolysis of $S_2Cl_2$ is tetrasulfur tetranitride ($S_4N_4$).
- Ammonium chloride ($NH_4Cl$) is also usually formed as a byproduct.
Reaction Overview
While the specific reaction pathway and stoichiometry can be complex depending on conditions, the main sulfur-containing product is $S_4N_4$. A simplified representation highlights this transformation: $ S_2Cl_2 + NH_3 \rightarrow S_4N_4 + NH_4Cl $ (Note: This equation needs balancing for accurate representation.)
Therefore, the ammonolysis of $S_2Cl_2$ in an inert solvent yields $S_4N_4$.
Important Questions from p Block Elements
Borax on treatment with NaOH and $H_2O_2$ forms X. The compound X on reaction with PhCN at $60$ °C in methanol-water mixture gives Y as the major product.
X and Y, respectively, are- The reaction of $P_2O_5$ with $HNO_3$ and $HClO_4$, respectively, gives
- The ease of formation of the adduct, $NH_3 \cdot BX_3$ (where, $X = F, Cl, Br$) follows the order
- In cyclophosphazenes, $(NPX_2)_3$ (X = F, Cl, Br and Me), the strength of P-N $\pi$-bond varies with X in the order
- Among the following, the group of molecules that undergoes rapid hydrolysis is
