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Question

In an exponentially growing batch culture of Saccharomyces cerevisiae, the cell density is 20 $gl^{-1}$ (DCW), the specific growth rate ($\mu$) is 0.4 $h^{-1}$ and substrate uptake rate (v) is 16 $gl^{-1}h^{-1}$. The cell yield coefficient $Y_{x/s}$ will be

The correct answer is
0.5

Yield Coefficient Calculation for Batch Culture

This solution explains how to calculate the cell yield coefficient ($Y_{x/s}$) for Saccharomyces cerevisiae in an exponential batch culture using the provided growth parameters.

Batch Culture Parameters

  • Cell Density (X): 20 $gl^{-1}$ (Dry Cell Weight)
  • Specific Growth Rate ($\mu$): 0.4 $h^{-1}$
  • Substrate Uptake Rate (v): 16 $gl^{-1}h^{-1}$

Biomass Production Rate

The rate at which biomass increases per unit volume ($dX/dt$) during exponential growth is calculated using the specific growth rate ($\mu$) and the current cell density ($X$):

$ \frac{dX}{dt} = \mu X $

Substitute the given values:

$ \frac{dX}{dt} = (0.4 \, h^{-1}) \times (20 \, gl^{-1}) = 8 \, gl^{-1}h^{-1} $

Yield Coefficient Definition

The cell yield coefficient ($Y_{x/s}$) quantifies the efficiency of converting substrate into biomass. It is defined as the ratio of biomass produced to the substrate consumed:

$ Y_{x/s} = \frac{\text{Biomass Produced}}{\text{Substrate Consumed}} $

In terms of volumetric rates during active growth, this becomes:

$ Y_{x/s} = \frac{dX/dt}{-dS/dt} $

Where $-dS/dt$ is the rate of substrate consumption per unit volume.

Final Yield Coefficient Calculation

The given substrate uptake rate (v) directly represents the rate of substrate consumption per unit volume ($-dS/dt$).

$ Y_{x/s} = \frac{8 \, gl^{-1}h^{-1}}{16 \, gl^{-1}h^{-1}} $

$ Y_{x/s} = 0.5 $

Therefore, the cell yield coefficient ($Y_{x/s}$) is 0.5.

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Important Questions from Kinetics of Cell Growth Substrate Utilization and Product Formation

  1. If the rate at which $E. coli$ divides is $0.5 \text{ h}^{-1}$, then its doubling time is _______________ h.

  2. Which of the following factors can affect the growth of a microbial culture in a batch cultivation process?
  3. Let $y(t)$ be a bacterial population whose growth is given by 

          $ \frac{dy}{dt} = \lambda(y + 2) $ 

    where $ \lambda $ is the growth rate constant. If $y(0) = 1$ and $y(1) = 4$, then the value of $ \lambda $ is

  4. If the doubling time of a bacterial population is 3 hours, then its average specific growth rate during this period is _________ $h^{-1}$. 

    (Round off to two decimal places)

  5. A microorganism is grown in a batch culture using glucose as a carbon source. The apparent growth yield is $0.5 \frac{\text{g biomass}}{\text{g substrate}}$. The initial concentrations of biomass and substrate are $2 \text{ g L}^{-1}$ and $200 \text{ g L}^{-1}$, respectively. Assuming that there is no endogenous metabolism, the maximum biomass concentration that can be achieved is ________ $\text{g L}^{-1}$.
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