In ΔABC, ∠A = 48°. If the bisectors of ∠B and ∠C meet at I, then the measure of ∠BIC will be:
114°
In geometry, when the internal angle bisectors of two angles in a triangle intersect, they meet at a special point called the incenter. This point is crucial for understanding various properties of triangles, especially those related to inscribed circles. The problem asks us to find the measure of the angle formed at this incenter when given one of the triangle's angles.
For any ΔABC, if the angle bisectors of ∠B and ∠C meet at point I (the incenter), the measure of ∠BIC can be determined using a specific formula. This formula connects the angle at the incenter to the angle opposite to the side that forms the base of the incenter angle (∠A in this case).
The formula is:
$$\angle\text{BIC} = 90^\circ + \frac{\angle\text{A}}{2}$$
This formula arises from applying the angle sum property of triangles. In ΔBIC, the sum of its angles is 180°. Since BI and CI are angle bisectors, ∠IBC = ∠B/2 and ∠ICB = ∠C/2. Using the sum of angles in ΔABC (∠A + ∠B + ∠C = 180°), we can substitute and simplify to arrive at the formula above.
We are given the following information for ΔABC:
Our goal is to find the measure of ∠BIC.
We will use the established formula for the angle formed by the internal angle bisectors at the incenter:
$$\angle\text{BIC} = 90^\circ + \frac{\angle\text{A}}{2}$$
Now, substitute the given value of ∠A (48°) into the formula:
$$\angle\text{BIC} = 90^\circ + \frac{48^\circ}{2}$$
First, perform the division:
$$\frac{48^\circ}{2} = 24^\circ$$
Next, add this result to 90°:
$$\angle\text{BIC} = 90^\circ + 24^\circ$$
Finally, calculate the sum:
$$\angle\text{BIC} = 114^\circ$$
Based on the geometric properties of triangle angle bisectors, the measure of ∠BIC, where I is the incenter formed by the bisectors of ∠B and ∠C in ΔABC with ∠A = 48°, is calculated to be 114°.
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