In a \(\triangle ABC\), \(\angle A:\angle B:\angle C=2:3:4\). A line (l) is drawn parallel to BA, then the \(\angle ACD\) is:
40°
Since angle A : angle B : angle C = 2:3:4 and they sum to 180 degrees, angle A = 40 degrees. Since CD is parallel to BA, angle ACD equals angle BAC (alternate angles with AC as transversal) = 40 degrees.
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