In a \(\triangle ABC\), \(\angle A:\angle B:\angle C=2:3:4\). A line (l) is drawn parallel to BA, then the \(\angle ACD\) is:
40°
Since angle A : angle B : angle C = 2:3:4 and they sum to 180 degrees, angle A = 40 degrees. Since CD is parallel to BA, angle ACD equals angle BAC (alternate angles with AC as transversal) = 40 degrees.
Similar Questions
In an equilateral triangle of side 24 cm, a circle is inscribed touching its sides. Find area of remaining portion of the triangle
(Take √3 = 1.732).
In the given \(\triangle ABC\), \(DE\parallel BC\). If \(BC=8\) cm, \(DE=6\) cm and area of \(\triangle ADE=90\) cm², then what is the area of \(\triangle ABC\) (in cm²)?
Important Questions from Triangles
What is the circumcenter of the triangle ABC?
What is the centroid of the triangle ABC?
What is the foot of the altitude from the vertex A of the triangle ABC?
In ΔABC, D is a point on BC such that ∠ADB = 2∠DAC, ∠BAC = 70° and ∠B = 56°. What is the measure of ∠ADC?
In ΔABC, ∠A = 66° and ∠B = 50 °. If the bisectors of ∠B and ∠C meet at P, then ∠BPC – ∠PCA = ?
