We need to determine the difference in incorrect answers between Candidate A and Candidate B, given they scored equally.
Let $C_A$ and $I_A$ be the number of correct and incorrect answers for Candidate A, respectively.
Let $C_B$ and $I_B$ be the number of correct and incorrect answers for Candidate B, respectively.
From the number of questions attempted:
From the equal marks scored:
Marks for A = Marks for B
$ 4 \times C_A - 1 \times I_A = 4 \times C_B - 1 \times I_B $
Substitute the expressions for $C_A$ and $C_B$ from the attempt equations into the marks equation:
$ 4(18 - I_A) - I_A = 4(13 - I_B) - I_B $
Simplify the equation:
$ 72 - 4I_A - I_A = 52 - 4I_B - I_B $
$ 72 - 5I_A = 52 - 5I_B $
Rearrange the terms to find the difference $I_A - I_B$:
$ 72 - 52 = 5I_A - 5I_B $
$ 20 = 5(I_A - I_B) $
$ I_A - I_B = \frac{20}{5} $
$ I_A - I_B = 4 $
Therefore, Candidate A has 4 more incorrect answers compared to Candidate B.