In a molecule of water, the ratio of the mass of hydrogen to that of oxygen is:
1 ∶ 8
The question asks for the ratio of the mass of hydrogen to that of oxygen in a molecule of water. A water molecule has the chemical formula $\text{H}_2\text{O}$. This means each water molecule contains two hydrogen atoms and one oxygen atom.
To find the mass ratio, we need to consider the atomic masses of hydrogen and oxygen.
In one molecule of water ($\text{H}_2\text{O}$):
The ratio of the mass of hydrogen to the mass of oxygen is the total mass of hydrogen divided by the total mass of oxygen.
Mass of Hydrogen : Mass of Oxygen
$2 \text{ amu} : 16 \text{ amu}$
To simplify this ratio, we can divide both sides by the greatest common divisor, which is 2.
$\frac{2}{2} : \frac{16}{2}$
$1 : 8$
So, the ratio of the mass of hydrogen to that of oxygen in a water molecule is $1 : 8$.
Let's look at the options provided:
Our calculated ratio $1 : 8$ matches the first option.
| Element | Symbol | Number of Atoms in $\text{H}_2\text{O}$ | Approximate Atomic Mass (amu) | Total Mass in $\text{H}_2\text{O}$ (amu) |
|---|---|---|---|---|
| Hydrogen | H | 2 | 1 | $2 \times 1 = 2$ |
| Oxygen | O | 1 | 16 | $1 \times 16 = 16$ |
Mass Ratio (Hydrogen : Oxygen) = Total Mass of Hydrogen : Total Mass of Oxygen = $2 : 16 = 1 : 8$.
Understanding mass ratios in chemical compounds is fundamental in chemistry. It helps in several areas:
While we used approximate atomic masses here, more precise calculations would use the average atomic masses from the periodic table (e.g., H $\approx$ 1.008 amu, O $\approx$ 15.999 amu). However, for introductory purposes, using whole numbers is common and gives the simplified integer ratio accurately.
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