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Question

In a code language SMART is coded as TODVY then what will be the code for CLOSE ?

This question was previously asked in
MH SET 2026 Paper 1 Question Paper (25-Oct-2026)
The correct answer is

DNRWJ

In letter-shifting codes each letter of the word is moved forward or backward in the alphabet by a fixed or changing amount. Write the alphabet positions (\(A = 1\), \(B = 2\), ... \(Z = 26\)) of the given word and its code, find the shift applied to each position, and then apply the same shifts, in the same order, to the new word.

Shifts in SMART to TODVY:
\(S (19) + 1 = 20 = T\)
\(M (13) + 2 = 15 = O\)
\(A (1) + 3 = 4 = D\)
\(R (18) + 4 = 22 = V\)
\(T (20) + 5 = 25 = Y\)
So the pattern is +1, +2, +3, +4, +5.
Apply to CLOSE:
\(C (3) + 1 = 4 = D\)
\(L (12) + 2 = 14 = N\)
\(O (15) + 3 = 18 = R\)
\(S (19) + 4 = 23 = W\)
\(E (5) + 5 = 10 = J\)
Code = DNRWJ

EMPVJ begins with E, which would need a shift of +2 on C, and it also uses a shift of +1 on L. DMQUJ uses +1 on L instead of +2. DNPVJ gives P for \(O (+1)\) and V for \(S (+3)\), so its third and fourth letters break the increasing pattern. Only DNRWJ follows the +1, +2, +3, +4, +5 rule at every position.

Hence, DNRWJ.

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