In a class of 50 students, the marks obtained are Marks 15 30 37 40 45 48 No. of students 2 8 14 12 10 4 Its median is
40
To find the median marks for the 50 students, we first need to arrange the data and calculate the cumulative frequency.
The given data is:
| Marks | No. of students (Frequency) | Cumulative Frequency (CF) |
| 15 | 2 | 2 |
| 30 | 8 | 10 (2 + 8) |
| 37 | 14 | 24 (10 + 14) |
| 40 | 12 | 36 (24 + 12) |
| 45 | 10 | 46 (36 + 10) |
| 48 | 4 | 50 (46 + 4) |
The total number of students, N, is 50.
The median is the middle value in an ordered dataset. Since the total number of students (N) is 50, which is an even number, the median is the average of the two middle values.
The positions of these middle values are calculated as:
So, the median is the average of the marks obtained by the 25th and 26th students.
We use the cumulative frequency (CF) column to find the marks corresponding to the 25th and 26th students:
Therefore:
To find the median, we calculate the average of the marks for the 25th and 26th students:
$$ \text{Median} = \frac{\text{Marks of 25th student} + \text{Marks of 26th student}}{2} $$
$$ \text{Median} = \frac{40 + 40}{2} $$
$$ \text{Median} = \frac{80}{2} $$
$$ \text{Median} = 40 $$
Thus, the median marks obtained by the students is 40.
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