Find the median if the given data set is: 3, 3, 7, 8, 12, 13, 16, 19
10
The median is the middle value in a dataset that is ordered from least to greatest. It is a measure of central tendency.
To find the median, we first need to arrange the data in ascending or descending order. The given dataset is:
3, 3, 7, 8, 12, 13, 16, 19
The data is already sorted in ascending order.
Next, we count the number of data points in the dataset. Let 'n' be the number of data points.
Since 'n' (8) is an even number, the median is the average of the two middle terms. The positions of the two middle terms are the \( \left(\frac{n}{2}\right)^{\text{th}} \) term and the \( \left(\frac{n}{2} + 1\right)^{\text{th}} \) term.
Now, we identify the 4th and 5th terms in the sorted dataset:
3, 3, 7, 8, 12, 13, 16, 19
The median is the average of these two terms:
\( \text{Median} = \frac{\text{4th term} + \text{5th term}}{2} \)
\( \text{Median} = \frac{8 + 12}{2} \)
\( \text{Median} = \frac{20}{2} \)
\( \text{Median} = 10 \)
Therefore, the median of the given dataset is 10.
In a class of 50 students, the marks obtained are
Marks | 15 | 30 | 37 | 40 | 45 | 48 |
No. of students | 2 | 8 | 14 | 12 | 10 | 4 |
Its median is
Let X be a normal random variable with mean zero and variance 9. If a = P(X ≥ 3) then P(|X| ≤ 3) equals:
A machine produces 0, 1 or 2 defective pieces in a day with an associated probability of \(\frac{{1}}{{6}}\), \(\frac{{2}}{{3}}\) and \(\frac{{1}}{{6}}\) respectively. The mean value and the variance of the number of defective pieces produced by the machine in a day, respectively, are
The median of 7, 5, 8, x, 12, 17 is 10, then what is the value of x?
Which one is parameter from population?