To determine the number of electrons (\(x\)) and nucleons (\(y\)) in the given sulfur ion, \({}_{16}^{32}S^{2-}\), we need to interpret the notation.
The number of nucleons is the mass number (\(A\)). In \({}_{16}^{32}S^{2-}\), the mass number \(A\) is 32.
Therefore, \(y = 32\).
The atomic number \(Z\) is 16, which means a neutral sulfur atom has 16 protons and 16 electrons.
The ion has a charge of \(2-\). This indicates that the atom has gained 2 electrons compared to the neutral state.
Number of electrons (\(x\)) = Number of protons + Charge magnitude
Number of electrons (\(x\)) = \(16 + 2 = 18\).
Based on the calculations:
This corresponds to the option where \(x = 18\) and \(y = 32\).
The four quantum numbers of the valence electron of potassium atom are:
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