Calculating Electrons and Nucleons in \({}_{16}^{32}S^{2-}\) Ion
To determine the number of electrons (\(x\)) and nucleons (\(y\)) in the given sulfur ion, \({}_{16}^{32}S^{2-}\), we need to interpret the notation.
Understanding the Notation \({}_{Z}^{A}X^{charge}\)
- The subscript \(Z\) represents the atomic number (number of protons).
- The superscript \(A\) represents the mass number (total number of nucleons: protons + neutrons).
- The chemical symbol \(X\) represents the element.
- The superscript indicating the charge shows the net charge of the ion.
Determining the Number of Nucleons (\(y\))
The number of nucleons is the mass number (\(A\)). In \({}_{16}^{32}S^{2-}\), the mass number \(A\) is 32.
Therefore, \(y = 32\).
Determining the Number of Electrons (\(x\))
The atomic number \(Z\) is 16, which means a neutral sulfur atom has 16 protons and 16 electrons.
The ion has a charge of \(2-\). This indicates that the atom has gained 2 electrons compared to the neutral state.
Number of electrons (\(x\)) = Number of protons + Charge magnitude
Number of electrons (\(x\)) = \(16 + 2 = 18\).
Conclusion
Based on the calculations:
- Number of electrons (\(x\)) = 18
- Number of nucleons (\(y\)) = 32
This corresponds to the option where \(x = 18\) and \(y = 32\).
Important Questions from Atomic Structure
Which of the following pairs of 'number – composition' is correct?
I. Atomic number – number of protons
II. Mass number – Sum of number of neutrons and protons
Which are the four quantum numbers for an electron present in 4f orbital?
What is the atomic number of Bohrium which is named after physicist Niels Bohr, one of the founders of quantum theory?
The quantum numbers n and l for four electrons are given below.
(i) n = 4, I = 1
(ii) n = 4, l = 0
(iii) n = 3, l = 2
(iv) n = 3, l = 1
The order of their energy from lowest to highest is:
The de-Broglie wavelength of a particle of mass 0.001 kg and moving with velocity 100 m/s is given by:
