N atom has 3 unpaired electrons because of
Hund’s rule
The electron configuration of an atom describes how electrons are distributed in its atomic orbitals. This distribution follows specific rules and principles of quantum mechanics, which helps explain the chemical properties of elements. Let's look at Nitrogen (N), which has an atomic number of 7, meaning it has 7 electrons.
Electrons fill the orbitals according to several fundamental rules:
Nitrogen has 7 electrons. Applying the principles:
According to Hund's Rule, these three $2p$ electrons will occupy each of the three $2p$ orbitals singly before any pairing occurs. They will also have parallel spins. So, the configuration for the $2p$ subshell is $2p_x^1 2p_y^1 2p_z^1$, with each electron having the same spin direction.
The full electron configuration for Nitrogen is $1s^2 2s^2 2p^3$.
In the $2p$ subshell, there is one electron in each of the three $2p$ orbitals. Since none of these electrons are paired with another electron in the same orbital, Nitrogen has 3 unpaired electrons.
This specific arrangement of unpaired electrons in the $2p$ subshell is a direct consequence of Hund's rule, which dictates the filling order within degenerate orbitals. While the Aufbau principle determines the energy level order ($1s \rightarrow 2s \rightarrow 2p$), and Pauli's exclusion principle limits each orbital to two electrons with opposite spins, it is Hund's rule that explains why the three $2p$ electrons occupy the three separate $2p$ orbitals singly with parallel spins, leading to three unpaired electrons.
Which one among the following statements is not true for glass?
The radius of an atomic nucleus is of the order of