We are given the vectors:
And the following conditions relating them to an unknown vector $\vec{c}$:
The objective is to determine the value of the expression $\vec{c} \cdot (\vec{a} - 2\vec{b})$.
First, expand the target expression using the properties of the dot product:
$ \vec{c} \cdot (\vec{a} - 2\vec{b}) = \vec{c} \cdot \vec{a} - \vec{c} \cdot (2\vec{b}) $
Rearrange and use the commutative property of the dot product ($\vec{c} \cdot \vec{a} = \vec{a} \cdot \vec{c}$):
$ = \vec{a} \cdot \vec{c} - 2(\vec{b} \cdot \vec{c}) $
1. Value of $\vec{a} \cdot \vec{c}$:
The problem explicitly states that $\vec{a} \cdot \vec{c} = 3$. No calculation is needed.
2. Value of $\vec{b} \cdot \vec{c}$:
We use the given cross product condition $\vec{a} \times \vec{c} = \vec{b}$.
To find $\vec{b} \cdot \vec{c}$, we can take the dot product of both sides of the cross product equation with $\vec{c}$:
$ \vec{c} \cdot (\vec{a} \times \vec{c}) = \vec{c} \cdot \vec{b} $
The left side, $\vec{c} \cdot (\vec{a} \times \vec{c})$, is a scalar triple product, specifically $[\vec{c}, \vec{a}, \vec{c}]$.
A key property of the scalar triple product is that it equals zero if any two of the vectors involved are identical. Here, the first and third vectors are both $\vec{c}$.
Therefore, $\vec{c} \cdot (\vec{a} \times \vec{c}) = 0$.
This leads to $\vec{c} \cdot \vec{b} = 0$, which means $\vec{b} \cdot \vec{c} = 0$.
Now, substitute the values of the dot products into the simplified expression:
$ \vec{c} \cdot (\vec{a} - 2\vec{b}) = \vec{a} \cdot \vec{c} - 2(\vec{b} \cdot \vec{c}) $
$ = 3 - 2(0) $
$ = 3 - 0 $
$ = 3 $
The final value of the expression is 3.