This problem involves finding the lateral surface area of a cube when its volume is given. To solve this, we first need to determine the length of one side of the cube using the provided volume.
The volume ($V$) of a cube is calculated by cubing its side length ($a$). The formula is:
$V = a^3$
We are given that the volume of the cube is $42,875 \text{ m}^3$.
To find the side length ($a$), we need to take the cube root of the volume:
$a = \sqrt[3]{V}$
Substitute the given volume into the equation:
$a = \sqrt[3]{42,875 \text{ m}^3}$
To find the cube root of 42,875, we look for a number that, when multiplied by itself three times, results in 42,875. Since the number ends in 5, its cube root must also end in 5. Testing $35$:
$35 \times 35 \times 35 = 1225 \times 35 = 42,875$
Thus, the side length of the cube is $a = 35$ meters.
The lateral surface area (LSA) of a cube is the total area of its four vertical faces. The formula for the LSA is:
$LSA = 4a^2$
Now, we substitute the side length we found ($a = 35$ m) into this formula:
$LSA = 4 \times (35 \text{ m})^2$
First, calculate the area of one square face ($a^2$):
$a^2 = (35 \text{ m})^2 = 1225 \text{ m}^2$
Next, multiply the area of one face by 4 to find the total lateral surface area:
$LSA = 4 \times 1225 \text{ m}^2$
$LSA = 4900 \text{ m}^2$
Therefore, the lateral surface area of the cube is $4900 \text{ m}^2$.
There is a wooden block in the form of a cube whose each side is 8 meters long.
The maximum possible number of cylinders with a diameter of 1 meter and a height of 4 meters were cut from this block. The cylinders are to be painted at the rate of ₹14 per square meter.
What is the total amount (in ₹) needed to paint all the cylinders if we paint the entire surface of each cylinder? (Take $\pi = \frac{22}{7}$)