The third proportional of two numbers, say a and b, is a number x such that the ratio of the first number to the second number is equal to the ratio of the second number to the third proportional. This can be expressed as:
$a : b = b : x$
This proportion implies the equation:
$\frac{a}{b} = \frac{b}{x}$
Rearranging the formula to solve for x, we get:
$x = \frac{b^2}{a}$
Given the numbers a = 25 and b = 35, we need to find the third proportional, x.
$x = \frac{35^2}{25}$
$x = \frac{1225}{25}$
$x = \frac{1225 \div 25}{25 \div 25} = \frac{49}{1}$
Alternatively, simplify using factors:$x = \frac{(35) \times (35)}{25} = \frac{(5 \times 7) \times (5 \times 7)}{5 \times 5} = \frac{25 \times 49}{25} = 49$
The third proportional of 25 and 35 is 49.
The cost of a diamond is directly proportional to the square of its weight. The cost of a 14 gm diamond is Rs. 2560. This diamond got broken down into two pieces in the ratio of 5 ∶ 9. How much loss percent is incurred due to this breakage ? (Correct to two decimal places)
Atul purchased Bread costing Rs.20 and gave a 100 rupee note to the shopkeeper. The shopkeeper gave the balance money in coins of denomination Rs.2, Rs.5 and Rs.10. If these coins are in the ratio 5 ∶ 4 ∶ 1, then how many Rs.5 coins did the shopkeeper give?
A person divides a certain amount among his three sons in the ratio of 3 ∶ 4 ∶ 5. If he had divided this amount in the ratio of 1/3,1/4,1/5, his son, who had got the lowest share earlier, would get Rs.1,188 more. Find the amount (in Rs).
In a school 3/8 of the number of students are girls and the rest are boys. One-third of the number of boys are below 10 years and 2/3 the number if girls are also below 10 years. If the number of students of age 10 or more years is 260. then the number of boys in the school is:
If a : b : c = \(\frac{1}{4} : \frac{1}{3} : \frac{1}{2}, \) then \( \ \frac{a}{b} : \frac{b}{c} : \frac{c}{a} = ?\)