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Question

If the pyrollidine ring of proline is reduced to a linear form, the new amino acid will have

The correct answer is

relaxed ϕ than proline

Proline is a unique amino acid because its side chain is cyclic, forming a ring with the nitrogen atom of the amino backbone. This cyclic structure, called the pyrrolidine ring, significantly impacts the flexibility around the peptide bond.

Proline Structure and Angles

In any amino acid within a polypeptide chain, there are dihedral angles that describe the rotation around bonds in the backbone:

  • The $\varphi$ (phi) angle represents the rotation around the bond between the nitrogen atom (N) and the alpha carbon ($\text{C}_\alpha$).
  • The $\psi$ (psi) angle represents the rotation around the bond between the alpha carbon ($\text{C}_\alpha$) and the carbonyl carbon (C).

For most amino acids, these angles have a wide range of possible values, although some angles are unfavorable due to steric clashes (as shown in a Ramachandran plot).

In proline, the pyrrolidine ring is formed by the side chain connecting back to the nitrogen atom. This ring includes the nitrogen, $\text{C}_\alpha$, $\text{C}_\beta$, $\text{C}_\gamma$, and $\text{C}_\delta$ atoms. The formation of this ring locks the $\varphi$ angle into a very narrow range, typically around $-60^{\circ}$. This makes the backbone significantly less flexible at proline residues compared to other amino acids.

Reducing the Pyrrolidine Ring

When the pyrrolidine ring of proline is reduced to a linear form, it means the cyclic structure is broken. Specifically, the bond connecting the $\delta$-carbon ($\text{C}_\delta$) back to the nitrogen atom is cleaved or opened up. This process would convert the cyclic side chain into a linear side chain attached to the $\text{C}_\alpha$ carbon, and the nitrogen atom would now have its standard three bonds (to $\text{C}_\alpha$, to the preceding carbonyl carbon, and a hydrogen atom), similar to other amino acids like leucine or isoleucine (depending on the exact linear structure formed).

Impact on Dihedral Angles

With the pyrrolidine ring opened, the restriction it imposed on the rotation around the $\text{N}-\text{C}_\alpha$ bond is removed. The nitrogen atom and the $\text{C}_\alpha$ carbon are now free to rotate relative to each other over a much wider range of angles, just like in standard amino acids. This means the constraint on the $\varphi$ angle is significantly reduced.

The $\psi$ angle is the rotation around the $\text{C}_\alpha-\text{C}$ bond. While the ring structure in proline does somewhat influence the allowed values for $\psi$, the most dramatic effect is on $\varphi$. When the ring is broken, the freedom of rotation around $\text{C}_\alpha-\text{C}$ (the $\psi$ angle) might also change compared to proline, but the primary consequence of breaking the ring connected to the nitrogen is the relaxation of the $\varphi$ angle constraint.

Let's analyze the options:

  • Option 1: constrained $\varphi$ than proline. Incorrect, the constraint is removed or reduced.
  • Option 2: constrained $\psi$ than proline. Incorrect, the primary effect is on $\varphi$, and it doesn't necessarily become *more* constrained $\psi$.
  • Option 3: relaxed $\varphi$ than proline. Correct, breaking the ring allows more freedom of rotation for the $\varphi$ angle.
  • Option 4: unaffected $\varphi$ and $\psi$. Incorrect, the angles are definitely affected, particularly $\varphi$.

Therefore, reducing the pyrrolidine ring of proline to a linear form leads to a relaxed $\varphi$ angle compared to the highly constrained $\varphi$ angle found in proline.

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Important Questions from Conformation of Proteins and Nucleic acids

  1. Which one of the following statements is true regarding amino acids?

  2. A form and Z form of double stranded DNA differ in the handedness of their helices, nucleotide sequences, and configuration of base to sugar. Based on these properties, which one of the following statements defines a correct combination for A and Z forms of DNA?

  3. The following statements are made

    A. B form of DNA has ~10 base pairs/turn and A form of DNA has ~2.3Å helix rise per base pair

    B. Both the A and B form of DNA have wider major groove and narrow minor groove

    C. The crystalline nature of cellulose is brought about by α (1 → 4) linkage between the glucose subunits.

    D. The double bonds in natural lipids are always cis, which provides fluidity to the plasma membrane.

    Which of the following combinations represent the correct statements?

  4. Analysis of a homotetrameric protein and a double stranded DNA (that had been incubated in standard buffer) on native gels revealed that they migrated true to their physical states (tetrameric nature of the protein and double stranded nature of the DNA). Following hypotheses were made for the effect of adding high salt to the incubation mix and subsequent analysis on native gels.

    A. The protein would migrate as a homotetramer and DNA in double stranded form.

    B. The protein would migrate as a monomer but DNA in double stranded form.

    C. The protein would migrate as a homotetramer but the DNA in single stranded form.

    D. The protein would migrate as a monomer and the DNA in single stranded form.

    Which of the following combination of hypotheses is most likely?

  5. Heating of some nucleic acids shows an increase in the absorbance at 260 nm (A260) typified by the plot shown above. The sharp transition midpoint is defined as melting temperature (Tm). Which one of the following nucleic acid samples is NOT expected to generate such a typical profile upon heating of its solution?

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