This problem requires finding the radius of a sphere where its volume and surface area have the same numerical value. We will use the standard formulas for a sphere's volume and surface area.
Here, '$r$' represents the radius of the sphere.
The condition given is that the numerical value of the volume is equal to the numerical value of the surface area:
$V = A$
Substitute the formulas:
$\frac{4}{3}\pi r^3 = 4\pi r^2$
To find the radius '$r$', we can simplify the equation. Assuming the radius is not zero ($r \neq 0$), we can divide both sides by common factors like $4\pi r^2$.
Therefore, the radius of the sphere is 3 units.