If P and Q together can do a job in 15 days, Q and R together can do it in 12 days and P and R together can do the same in 20 days, then in how many days will the job be completed, if all the three work together?
10 days
This problem is a classic example of a time and work question involving multiple individuals working together. We are given the time it takes for pairs of individuals (P and Q, Q and R, P and R) to complete a job and need to find the time it takes for all three (P, Q, and R) to complete the same job.
The key concept in solving time and work problems is the work rate. The work rate of an individual or a group is the amount of work they can complete in one unit of time (usually a day). If someone can complete a job in 'n' days, their work rate is \( \frac{1}{n} \) of the job per day.
Based on the given information, we can calculate the work rate for each pair:
Let P's work rate be \( w_P \), Q's work rate be \( w_Q \), and R's work rate be \( w_R \). From the information above, we have:
If we add these three equations together, we get:
\( (w_P + w_Q) + (w_Q + w_R) + (w_P + w_R) = \frac{1}{15} + \frac{1}{12} + \frac{1}{20} \)
\( 2w_P + 2w_Q + 2w_R = \frac{1}{15} + \frac{1}{12} + \frac{1}{20} \)
\( 2(w_P + w_Q + w_R) = \frac{1}{15} + \frac{1}{12} + \frac{1}{20} \)
Now, we need to find the sum of the fractions on the right side. The least common multiple (LCM) of 15, 12, and 20 is 60.
\( \frac{1}{15} = \frac{1 \times 4}{15 \times 4} = \frac{4}{60} \)
\( \frac{1}{12} = \frac{1 \times 5}{12 \times 5} = \frac{5}{60} \)
\( \frac{1}{20} = \frac{1 \times 3}{20 \times 3} = \frac{3}{60} \)
So, \( \frac{1}{15} + \frac{1}{12} + \frac{1}{20} = \frac{4}{60} + \frac{5}{60} + \frac{3}{60} = \frac{4+5+3}{60} = \frac{12}{60} = \frac{1}{5} \)
Therefore, \( 2(w_P + w_Q + w_R) = \frac{1}{5} \)
The combined work rate of P, Q, and R together \( (w_P + w_Q + w_R) \) is half of this value:
\( w_P + w_Q + w_R = \frac{1}{2} \times \frac{1}{5} = \frac{1}{10} \)
This means that P, Q, and R together can complete \( \frac{1}{10} \) of the job per day.
Since the combined work rate of P, Q, and R is \( \frac{1}{10} \) of the job per day, the total time taken for them to complete the entire job when working together is the reciprocal of their combined work rate.
Time taken = \( \frac{1}{\text{Combined work rate}} = \frac{1}{\frac{1}{10}} = 10 \) days.
| Pair | Time Taken (Days) | Work Rate (Job/Day) |
|---|---|---|
| P & Q | 15 | \( \frac{1}{15} \) |
| Q & R | 12 | \( \frac{1}{12} \) |
| P & R | 20 | \( \frac{1}{20} \) |
| P, Q & R (Combined Rate) | ? | \( \frac{1}{10} \) |
Thus, if P, Q, and R work together, they will complete the job in 10 days.
| Concept | Explanation | Formula |
|---|---|---|
| Work Rate | Amount of work done per unit of time. | Work Rate \( = \frac{1}{\text{Time Taken}} \) |
| Total Work | Usually considered as 1 unit (the whole job). | Total Work \( = \) Work Rate \( \times \) Time Taken |
| Combined Work Rate | Sum of individual work rates when multiple people work together. | \( (w_1 + w_2 + ...) \) |
| Time Taken by Multiple People | Reciprocal of their combined work rate. | Time \( = \frac{1}{\text{Combined Work Rate}} \) |
Time and work problems often involve scenarios where people work at different rates, sometimes individually, sometimes in groups, or even for different durations. Understanding the concept of work rate as the reciprocal of time taken is fundamental.
This problem involved finding the sum of individual rates from pairwise sums, which is a common technique in time and work questions.
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