If one angle of an isosceles triangle is 110°, what are the measures of the other angles of the triangle?
35° and 35°
In an isosceles triangle, the two base angles are equal, and all three angles sum to 180°.
Since 110° is too large to be one of two equal base angles (that would exceed 180°), it must be the unique vertex angle.
The remaining two equal angles: \(\dfrac{180-110}{2} = 35\)° each.
Hence, the other two angles measure 35° and 35°.
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