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Question

If N is the Brunt-Väisälä frequency, any air parcel with $N^2 < 0$ will be

This question was previously asked in
CSIR NET 2019 Earth Science Question Paper (15-Dec-2019)
The correct answer is
statically unstable.

Brunt-Väisälä Frequency and Stability Condition

The Brunt-Väisälä frequency, denoted by N, is a fundamental concept in fluid dynamics and atmospheric science that describes the natural frequency at which a parcel of fluid displaced vertically will oscillate due to buoyancy if the surrounding fluid is statically stable.

Stability Analysis Based on N2

The stability of the atmosphere (or any stratified fluid) is determined by the sign of N2:

  • Static Stability ($N^2 > 0$): If N2 is positive, buoyancy acts as a restoring force, causing the displaced parcel to oscillate around its equilibrium position.
  • Static Neutrality ($N^2 = 0$): If N2 is zero, there is no restoring or destabilizing force. The parcel remains in its new position after displacement.
  • Static Instability ($N^2 < 0$): If N2 is negative, buoyancy acts as an amplifying force, pushing the displaced parcel further away from its equilibrium position.

Condition for Instability

The question states that $N^2 < 0$. In this scenario, the square of the Brunt-Väisälä frequency is negative. This indicates that there is no restoring force acting on a displaced air parcel. Instead, the buoyant force will cause the parcel to accelerate away from its original position, leading to a condition of static instability.

Therefore, any air parcel with $N^2 < 0$ will be statically unstable.

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